The denominator : q² - 3q - 4 should be ≠ 0.
Let's find the zero values of this quadratic equation:
q' = [-b+√(b²-4.a.c)]/2.a and q'' = [-b-√(b<span>²-4.a.c)]/2.a
you will fond q' = 4 and q'' = -1
Then the restrictions are :
q </span>≠ 4 and q ≠ - 1 (1st answer)
Answer:
A and C
Step-by-step explanation:
Perpendicular lines have reciprocal and opposite slopes.
First slope =3,
Second = -3
Third slope = -1/3 (which is opposite and reciprocal to the first)
Last slope = -3
Answer:
We don't have the ability to tell
Step-by-step explanation:
(no image provided) Error: 362
Answer:
Step-by-step explanation:
8^2 + 15^2 = ?
64 + 225 = 17^2
289 = 289
