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3 years ago

Correct the comparison symbol

Mathematics

1 answer:

Alchen [17]3 years ago

6 0

For what number? do i just correct the ones you have or thell you all the answer?

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Mashcka [7]

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3 years ago

I need help solving number 11 please.

Mnenie [13.5K]

set up the triangle with the information given. then just solve for x.

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3 years ago

What is the solution to the equation<br> 1/2x+3 = 2/3+1?

Alex

Answer:

x = -8/3

Step-by-step explanation:

1/2x+3 = 2/3+1

Combine like terms

1/2x+3 = 2/3 + 3/3

1/2x + 3 = 5/3

Subtract 3 from each side

1/2x + 3-3 = 5/3 - 3

1/2x = 5/3 - 9/3

1/2x = -4/3

Multiply each side by 2

1/2x *2 = -4/3*2

x = -8/3

7 0

3 years ago

PLEASE HELP and Show your work please!!

bazaltina [42]

9514 1404 393

Answer:

2) 3 pages per hour

3) 4/29 km per minute

Step-by-step explanation:

Division by a fraction is the same as multiplication by the inverse of that fraction.

$\dfrac{\ \dfrac{9}{4}\ }{\dfrac{3}{4}}=\dfrac{9}{4}\times\dfrac{4}{3}=\dfrac{36}{12}=\boxed{3\text{ pages per hour}}$

$\dfrac{2\text{ km}}{\dfrac{29}{2}\text{ min}}=2\times\dfrac{2}{29}\text{ km/min}=\boxed{\dfrac{4}{29}\text{ km/min}}$

8 0

2 years ago

Remember to show work and explain. Use the math font.

vichka [17]

Answer:

$\large\boxed{1.\ f^{-1}(x)=\sqrt[12]{3^x}}\\\\\boxed{2.\ f^{-1}(x)=\sqrt[4]{3^x}}\\\\\ \boxed{3.\ f^{-1}(x)=\sqrt[3]{4^{7-x}}}$

Step-by-step explanation:

$(a^n)^m=a^{nm}\\\\\log_ab=c\iff a^c=b\\\\a^{\log_ax}=x\\\\n\log_ab=\log_ab^n\\\\\log_ab+\log_ac=\log_a(bc)\\============================\\\\1.\\y=3\log_3x^4\to y=\log_3(x^4)^3\to y=\log_3x^{12}$

$2.\\y=\log_3x^4\\\\\text{Exchange x and y. Solve for y:}\\\\\log_3y^4=x\Rightarrow3^{\log_3y^4}=3^x\Rightarrow y^{4}=3^x\\\\y=\sqrt[4]{3^x}\\-------------------------$

$3.\\y=-\log_4x^3+7\\\\\text{Exchange x and y. Solve for y:}\\\\-\log_4y^3+7=x\qquad\text{subtract 7 from both sides}\\\\-\log_4 y^3=x-7\qquad\text{change the signs}\\\\\log_4y^3=7-x\Rightarrow4^{\log_4y^3}=4^{7-x}\\\\y^3=4^{7-x}\Rightarrow y=\sqrt[3]{4^{7-x}}$

7 0

3 years ago