Problem 1:
11-c = -17
First, we need to isolate the term with the variable. We can simply do that by subtracting 11 from both sides as follows:
11-11-c = -17-11
-c = -28
Then, we will multiply both sides by -1 to get the positive value of c as follows:
-c x -1 = -28 x -1
c = 28
Problem 2:
1/2 y + 1/5 = 1/2
First, we need to isolate the term with the variable by subtracting 1/5 from both sides as follows:
1/2 y = 1/2 - 1/5 = 3/10
Then, we will get rid of the coefficient in the term with variable by dividong both sides with 1/2, this will give the following output:
y = 3/5
Answer:
0
Step-by-step explanation:
The slope of two parallel lines are the same, and the slope of y = 0x + 4 is 0, so the answer is 0.
The given lines are
x = 1 + t
y = 2t
z = -3t
The plane is x + y - z = 3
If the lines intersect the plane at a point p, then the lines should satisfy the equation of the plane.
That is,
(1 + t) + (2t) - (-3t) = 3
1 + t + 2t + 3t = 3
1 + 6t = 3
6t = 2
t = 1/3
Therefore the coordinates of the point p are
x = 1 + 1/3 = 4/3
y = 2(1/3) = 2/3
z = -3(1/3) = -1
That is p (4/3, 2/3, -1)
Answer: The point p has coordinates (4/3, 2/3, -1)
Answer:
A. (2, -1)
Step-by-step explanation:
(4x - 9) - x = -3
3x - 9 = - 3
3x = 6
x = 2
y = 4(2) - 9
y = 8 -9
y = - 1
(2, -1)
Check
-1 - 2 = -3
Step-by-step explanation:
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