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yanalaym [24]
3 years ago
13

Write an equation and solve: Twice a number, increased by 3 is 7.

Mathematics
2 answers:
Artist 52 [7]3 years ago
4 0
'number' will be x
2x+3=7
subtract 3 on both sides:
2x=4
divide by 2 on both sides:
x=2
So the answer to the problem is A
aivan3 [116]3 years ago
3 0
If this involves variables, then your equation can be

m times 2 + 3 = 7

M would be 2
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add the graph

Step-by-step explanation:

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30% and added to/subtracted from

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5 0
3 years ago
Brainliest + 20 pts to whoever helps pls!!
Blizzard [7]

Answer:

Correct option is (a). 60.391 and 101.879; because the test statistic is in a critical region, the test rejects the null hypothesis.

Step-by-step explanation:

A Chi-square test for population variance is used to perform this test.

The standard deviation is, 2.0 minutes.

Then the variance is, 4.0 minutes.

The hypothesis for this test is:

<em>H₀</em>: The population variance of all commute times is equal to 4.0 minutes, i.e. <em>σ² </em>= 4.

<em>Hₐ</em>: The population variance of all commute times is not equal to 4.0 minutes, i.e. <em>σ² </em>≠ 4.

The test statistic is:

\chi^{2}_{calc.}=\frac{(n-1)s^{2}}{\sigma^{2}}

The critical region of this test is defined as:

Reject <em>H₀</em> if \chi^{2}_{calc.} or \chi^{2}_{calc.}>\chi^{2}_{(1-\alpha /2), (n-1)}.

The degrees of freedom is:

n-1=81-1=80

Compute the critical from a Chi-square table.

\chi^{2}_{\alpha /2, (n-1)}=\chi^{2}_{0.05, 80}=101.879\\\chi^{2}_{(1-\alpha /2), (n-1)}=\chi^{2}_{0.95, 80}=60.391\\

The test statistic value is, \chi^{2}_{calc.}=105.8.

\chi^{2}_{calc.}=105.8 > \chi^{2}_{0.05, 80}=101.879

The null hypothesis is rejected because the test statistic is in the critical region.

Thus, the correct option is (a).

6 0
3 years ago
HCF(320, x) = 20, LCM(320, x) = 2240, then x =
HACTEHA [7]

Answer:

  140

Step-by-step explanation:

When working HCF and LCM problems, I like to think in terms of this little diagram:

  (a [ b ) c]

It shows me one of the numbers is ab, the other is bc, the HCF is b and the LCM is abc. "a" and "c" must be relatively prime for "b" to be the HCF.

__

Here, we're given ...

  b = 20

  ab = 320

  abc = 2240

Then ...

  c = abc/(ab) = 2240/320 = 7

  x = bc = 20(7) . . . . . . equivalently, x = (abc·b)/(ab) = (2240·20)/320

  x = 140

6 0
4 years ago
The manager suggests that Darryl should purchase the deli’s bread from Store D because they sell the most loaves of bread for th
mina [271]
<span>No, store D does not have the best deal when you compare the unit prices. The best deal isn’t from having more loaves. The best deal is from store B because the unit price is the lowest.</span>
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