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3 years ago

A) Simplify X-2 7(x - 2)2

Mathematics

2 answers:

STatiana [176]3 years ago

6 0

Answer:

7x^2 -28x +28

Step-by-step explanation:

7(x - 2)^2

7 ( x-2)(x-2)

Foil

7 ( x^2 -2x-2x+4)

Combine like terms

7( x^2 -4x+4)

Distribute

7x^2 -28x +28

Archy [21]3 years ago

4 0

Answer:

$\dfrac{1}{7x-14}$

Step-by-step explanation:

Perhaps you want to simplify ...

$\dfrac{x-2}{7(x-2)^2}=\dfrac{x-2}{x-2}\cdot\dfrac{1}{7(x-2)}=\boxed{\dfrac{1}{7x-14}}$

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2 years ago

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Solve the system of equations by any method. 5x+9y =16 x+2y =4

Alisiya [41]

Answer:

The system of equations has one solution at (-4, 4).

Step-by-step explanation:

We are given the system of equations:

$\displaystyle\left \{ {{5x+9y=16} \atop {x+2y=4}} \right.$

We can use elimination to solve this system. We need to multiply the second equation by -5 so we can cancel out our x-terms.

$-5\times(x+2y=4) \rightarrow -5x - 10y = -20$

Therefore, our system now becomes:

$\displaystyle\left \{ {{5x+9y=16} \atop {-5x-10y=-20}} \right.$

Now, we can add these two equations together and solve for y.

$\displaystyle(5x + 9y) + (-5x - 10y) = 0 - y\\\\16 + (-20) = -4\\\\-y = -4\\\\\frac{-y}{-1}=\frac{-4}{-1}\\\\y = 4$

Now, we can substitute our value for y into one of the equations and solve for x.

$x+2(4)=4\\\\x + 8 = 4\\\\x = -4$

Therefore, our final solution is (-4, 4).

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3 years ago

What is the highest common factor of 45 and 315?

7nadin3 [17]

The highest common factor is 45

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3 years ago

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If i have 10 apples and eat 5 how many do i have now?

Sliva [168]

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3 years ago

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Sam applies a force at 30° to the horizontal to move a football tackling dummy 10 m horizontally.

Basile [38]

Answer:

$F=\frac{32\sqrt{3}}{3}\text{\:or\:} \approx 18.48\:\text{N}$

Step-by-step explanation:

We can find the horizontal component of force he applied by using the formula for work:

$W=F\Delta x$

Solving for force, we have:

$160=F\cdot 10,\\F=16\:\text{N}$

However he applied the original force at an angle of $30^{\circ}$ to the horizontal. This force of 16 newtons is only the horizontal component of that force. To find the magnitude of the original force, we can use basic trigonometry:

$\cos 30^{\circ}=\frac{16}{x},\\x=\frac{16}{\cos 30^{\circ}},\\\\x=\frac{16}{\frac{\sqrt{3}}{2}},\\\\x=16\cdot\frac{2}{\sqrt{3}}=\frac{32}{\sqrt{3}}=\boxed{\frac{32\sqrt{3}}{3}}$

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3 years ago