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SIZIF [17.4K]
3 years ago
7

Clara estimates that the length of a hiking trail is 5.75 km. She later learns that its actual length is 6.25 km. What is the pe

rcent error in Clara's estimate, to the nearest tenth of a percent?
Mathematics
1 answer:
Hunter-Best [27]3 years ago
8 0
Percent error : (approximate value - exact value) / exact value.....x 100

percent error : (5.75 - 6.25) / 6.25......ignore any negative signs
0.5 / 6.25 = 0.08.....x 100 = 8% error <==
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Solve the inequality lxl &lt;5.
Lorico [155]

Answer:

can you check if you wrote this correctly

7 0
3 years ago
g (15 points) Suppose 42 out of 600 rats exposed to a potential carcinogen develop tumors. A control group of 350 rats not expos
vazorg [7]

Answer:

a) The relative risk is 1.8\overline{846153}

b) The attributable risk is 0.69 \overline{047619}

c) There is a relationship between exposure and tumor risk

Step-by-step explanation:

The number of exposed rats that develop tumors, a = 42

The number of rats exposed to the carcinogen = 600 rats

The number of exposed rats that did not develop tumors, b = 600 - 42 = 558

The number of not exposed rats in the control group = 350 rats

The number of rats that develop tumors in the control group, c = 13 tumors

The number of not exposed rats that did not develop tumors, d = 350 - 13 = 337  rats

a) The relative risk, RR = a/(a + b)/(c/(c + d))

∴ RR = (42/(42 + 558))/(13/(13 + 337)) = 49/26 = 1.8\overline{846153}

b) The attributable risk = (a - c)/a

∴ The attributable risk = (42 - 13)/42 = 0.69 \overline{047619}

c) The odds ratio = (a·b)/(c·d)

∴ The odds ratio = 42 × 558/(13 × 337) = 23439/4381 ≈ 5.35

Given that the result of attributable risk is positive, there is an indication that there is a higher probability to develop tumor when exposed to the potential carcinogen, therefore, there is a relationship between exposure and tumor risk

7 0
3 years ago
A certain organization recommends the use of passwords with the following​ format: vowel commavowel, consonant comma consonant c
zimovet [89]

The password format is = inpray93

vowel , consonant, consonant, consonant, vowel, consonant, number, number.

There are 21 consonants, 5 vowels and 10 number choices (0-9)

Since, there are 21 consonants and repetition is allowed so for 2nd, 3rd, 4th, and 6th positions 21 choices are available. For 1st and 5th positions, 5 choices  are available and for 7th and 8th position there are 10 choices (0 to 9).

Passwords are not case sensitive which means upper case and lower case letters are same.

So, the number of passwords can be =

5\times21\times21\times21\times5\times21\times10\times10

= 486202500

Part (b) question is not given. But it can be opposite to the first part i.e when the password letters are case sensitive.

This means all the letters are different.

So, number of passwords will be =

10\times42\times42\times42\times10\times42\times10\times10

= 31116960000

4 0
3 years ago
I need the 68th term help plz
Svet_ta [14]

Answer:

Since -14 is added in each term

Therefore,in 68 th term will be 68×-14 +(-19)

As the 1 st term is -19

68 th term= -952+(-19)

68 th term= -971

8 0
3 years ago
Write the slope intercept form of the equation of each line
Sphinxa [80]

Answer:

Y = -1/2x+4

Step-by-step explanation:

The Y intercept is 4, so that's where the +4 comes in.

The slope is rise over run, so you count how many up you go from a whole number, in this case one, and that goes on top. Then you count how many it goes over, in this case two, and that goes on the bottom. The negative comes from which way the slope is going; down or up.

3 0
3 years ago
Read 2 more answers
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