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padilas [110]
3 years ago
15

If 150g of sugar is used for 5 cakes How much is used for 7 cakes?:)

Mathematics
2 answers:
KIM [24]3 years ago
3 0
Well, if 150 grams is used for 5 cakes, we can divide that.
150/5=30. 30 grams of sugar are used for each cake
You want to know how many grams for 7 cakes
30x7=<u><em>210 grams of sugar are used for seven cakes.
</em></u>Hope this helps!<u><em>
</em></u>
anastassius [24]3 years ago
3 0
150 g - 5 cakes
x g - 7 cakes

x=\dfrac{7\cdot150}{5}\\&#10;x=210

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Shkiper50 [21]

Answer and Step-by-step explanation:

1-6

a.

What you can do is plug in 6 and start by doing the first machine first, then the second. If this doesn't work, do the second machine, then the first machine.

<em><u>The order that works is second machine, then first machine.</u></em>

<u>Second Machine:</u>

y = (6)^{2} -6 = 36 - 6 = 30

Plug into first machine now.

<u>First Machine:</u>

y = \sqrt{(30) - 5}  = \sqrt{25} = 5

We see that the result is 5.

b. <em><u>If we were to do the order of second machine, then first machine, we will never get a negative result (or -5 for that matter), due to the fact that you can't algebraically square root a negative number.</u></em>

<em><u>However, if we were to do the order of first machine, second machine, we can get a negative number. To get -5, we plug in 6 for x in the first machine, getting an answer of 1. We plug this into the second machine, getting 1^2 - 6, which results in -5.</u></em>

1-7. The absolute value of a value is the positive version of that value.

a. |54| = <em><u>54</u></em>

b. -|-7\frac{3}{5}| = -7\frac{3}{5}

c. |3| - |-1| = 3 - 1 = <em><u>2</u></em>

d. |2.2 - 5.13| = |-2.93| = <em><u>2.93</u></em>

1-8.

a.

_

<u>|  |</u>

<u>|  |</u>

<u>|  |</u>

<u>|  |</u>

<u>|  |</u> <u>  </u> <u>   </u> <u>  </u> <u>   </u>

<u>|  ||  ||  ||  ||  |</u>

<u>(5 boxes on each side)</u>

_

<u>|  |</u>

<u>|  |</u>

<u>|  |</u>

<u>|  |</u>

<u>|  |</u> <u>  </u> <u>   </u> <u>  </u> <u>   </u> <u>   </u>

<u>|  ||  ||  ||  ||  ||  |</u>

<u>(6 boxes on each side)</u>

b.<em><u> The amount of squares on each side of the figure increases by 1.</u></em>

c. <em><u>There would be 1 square, because we know that the pattern is there is 2 squares added to the next figure, 1 at each end. If we go back a figure, we take away 2 squares.</u></em>

1-9.

a. -42 - 17 = <em><u>-59</u></em>

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f. -18 - 7 = <em><u>-25</u></em>

g. (-5)^{2} = <em><u>25</u></em>

h. -5^{2}  = -(5)^2 = -(25) = <em><u>-25</u></em>

i. \sqrt{49} = <em><u>7</u></em>

1-10.  x = 2 Plug 2 in for x, then solve.

a. y = 7 - 3(2) = 7 - 6 = <em><u>1</u></em>

b. y = (2)^2 -1 = 4 - 1 = <em><u>3</u></em>

c. y = \frac{18}{2} = <em><u>9</u></em>

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

<em><u>I hope this helps!</u></em>

8 0
3 years ago
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