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Tanya [424]
3 years ago
6

23.A chef ordered 400 pounds of potatoes in same-sized bags. Which expressions show

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
5 0

Answer:

10*40

80*5

20*20

Step-by-step explanation:

20*20=400

80*5=400

10*40=400

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Answer:

Step-by-step explanation:

What diagram?

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Pls help due in 10 minutes!!!
Luden [163]

Answer:

\sf 500,000,000,000=5 \times 10^{11}

\sf 0.00000000005=5 \times 10^{-11}

Step-by-step explanation:

<u>Scientific notation</u>

\large\boxed{a \times 10^n}  

where:

  • 1\leq a < 10
  • n is any positive or negative <u>whole number</u>.

To convert a number into scientific notation, <u>move</u> the decimal point to the <u>left or right</u> until there is <u>one digit</u> to the left of the decimal point.

The number of times you have moved the decimal point is n.

  • If the decimal point has moved to the <u>left</u>, n is positive.
  • If the decimal point has moved to the <u>right</u>, n is negative.

To convert 500,000,000,000 into scientific notation, move the decimal point <u>11 places to left</u>, so a = 5.  As we have moved the decimal point 11 places to the left, the exponent "n" is 11 and is <u>positive</u>.

\implies \sf 500,000,000,000=5 \times 10^{11}

To convert 0.00000000005 into scientific notation, move the decimal point <u>11 places to the right</u>, so a = 5.  As we have moved the decimal point 11 places to the right , the exponent "n" is 11 and is <u>negative</u>.

\implies \sf 0.00000000005=5 \times 10^{-11}

Learn more about scientific notation here:

brainly.com/question/28235385

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2 years ago
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Millie borrowed $20 from her dad. Explain why this situation indicates a negative number for Millie even though $20 is a positiv
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Millie will have to pay the $20 back, and as she already has no money, she's now $20 in debt
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I need help on number 5
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C. Skewed

Step-by-step explanation:

You can tell because the box in this box and whisker plot is on the right side of the line meaning that it is skewed.

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3 years ago
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The web logs of a certain website show that the average number of hits in an hour is 75 with a standard deviation equal to 8.6.
Wittaler [7]

Answer:

a) There is a 10.75% probability of observing less than 60 hits in an hour.

b) The 99th percentile of the distribution of the number of hits is 95.21 hits.

c) There is a 24% probability of observing between 80 and 90 hits an hour

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem, we have that

The web logs of a certain website show that the average number of hits in an hour is 75 with a standard deviation equal to 8.6, so \mu = 75, \sigma = 8.6.

a) What’s the probability of observing less than 60 hits in an hour? Use the normal approximation

This is the pvalue of Z when X = 60. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{60 - 75}{8.6}

Z = -1.74

Z = -1.74 has a pvalue of 0.1075. This means that there is a 10.75% probability of observing less than 60 hits in an hour.

b) What’s the 99th percentile of the distribution of the number of hits?

What is the value of X when Z has a pvalue of 0.99.

Z = 2.35 has a pvalue of 0.99

So

Z = \frac{X - \mu}{\sigma}

2.35 = \frac{X - 75}{8.6}

X - 75 = 20.21

X = 95.21

The 99th percentile of the distribution of the number of hits is 95.21 hits.

c) What’s the probability of observing between 80 and 90 hits an hour?

This is the pvalue of the zscore of X = 90 subtracted by the pvalue of the zscore of X = 80.

For X = 90

Z = \frac{X - \mu}{\sigma}

Z = \frac{90 - 75}{8.6}

Z = 1.74

Z = 1.74 has a pvalue of 0.95907

For X = 80

Z = \frac{X - \mu}{\sigma}

Z = \frac{80 - 75}{8.6}

Z = 0.58

Z = 0.58 has a pvalue of 0.71904

So

There is a 0.95907 - 0.71904 = 0.24003 = 24% probability of observing between 80 and 90 hits an hour

6 0
3 years ago
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