Answer:
x>-11
Step-by-step explanation:
2x+8>-14
2x>-14-8
2x>-22
x>-22/2
x>-11
x>-11
First distribute the invisible 1 to the numbers in the parenthesis.
3x + 2 - 4x
Combine like terms.
-x + 2
At the beginning, there are 15 pigs without ribbons. one of the pigs receives a ribbon. how many are left ribbonless?
<span>14. when another pig is given a ribbon, there are 13 left. after all the ribbons have been given out, 3 of the 15 pigs have ribbons. </span>
<span>if any one of the 15 at the beginning is given a ribbon, there are 15 possible combos. for the second ribbon, there are 14 combos- but each of those combos has to go through the first 15. for the third ribbon, there are 13 combos, going through 14 and 15. </span>
<span>simply put, 15 x 14 x 13.</span>
Answer:
From the attached graphic, we can see:
(SP + PR) * PR = (WQ + QR) * QR
SP * PR + PR^2 = WQ * QR + QR^2
4 SP + 4*4 = 8 * 5 + 25
4 SP + 16 = 65
4 SP = 49
SP = 49 / 4
SP = 12.25
Step-by-step explanation:
