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erastovalidia [21]
2 years ago
12

If ∆ABC congruent ∆DEF, which of the following can you NOT conclude as being true?

Mathematics
2 answers:
Olin [163]2 years ago
6 0

Answer:

C

Step-by-step explanation:

enyata [817]2 years ago
4 0

Answer:

I believe the answer would be C (sorry i messed uo the first time)

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Con ayuda de tu familia formula un
Mademuasel [1]

https://youtu.be/GZcm4mswivc

espero que te ayude

5 0
3 years ago
The ABC Book Club charges a $40 monthly fee, plus $2 per book read in that month. The Easy Book Club charges a 35$ monthly fee,
MAVERICK [17]
The expression for the cost of the ABC Book Club is 2x + 40. The expression for the cost of the Easy Book Club is 3x + 35. To find when the total charge for both book clubs is equal, the two expressions must equal each other. (x = the number of books read)

2x + 40 = 3x + 35

Subtract 35 from both sides.

2x + 5 = 3x

Subtract 2x from both sides.

5 = x

So, the total charge for each club is equal when 5 books are read.
5 0
2 years ago
Write an equation describing the relationship of the given variables. y varies inversely as the cube root of x and when x=125, y
notka56 [123]

Answer:

y = 40 / x^1/3

Step-by-step explanation:

Given that :

y α x^1/3

y = k * 1 / x^1/3

y = k / x^1/3

When x = 125 ; y = 8

8 = k / 125^1/3

Cube root of 125 = 5

8 = k / 5

8 * 5 = k ; k = 40

Hence, expression becomes :

y = 40 / x^1/3

4 0
2 years ago
Questions 3-5 please and thank you
vekshin1

Answer:

too far away and too blurry cant see it

7 0
3 years ago
What is the range of the function f(x) = 3x2 + 6x – 8?
timama [110]

Answer:

Range is {y | y ≥ –11}


Step-by-step explanation:

This is quadratic equation.

<em>A quadratic equation's range can be found if we find the vertex.</em>

For quadratic equations that have a positive number in front of  x^{2} , it is upward opening and thus <u>all the numbers greater than or equal to the minimum value of vertex is the range.</u>


The formula for vertex of a parabola is:

Vertex =  (-\frac{b}{2a}, f(-\frac{b}{2a})

Where,

  • a is the coefficient of x^{2}
  • b is the coefficient of x

From our equation given, a=3  and  b=6

Now, x coordinate of vertex is  x=-\frac{b}{2a}\\x=-\frac{6}{(2)(3)}\\x=-\frac{6}{6}\\x=-1

y coordinate of the vertex IS THE MINIMUM VALUE that we want. We get this by plugging in the x value [ x=-1 ] into the equation. So we have:

3(-1)^{2}+6(-1)-8\\=-11


Hence, the range would be all numbers greater than or equal to -11  

Third answer choice is the right one.


6 0
2 years ago
Read 2 more answers
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