What is 1/4 shaded of 8 piece bar graph

A ladder 35 feet long is leaning against the wall of a house….. <br><br> Answers for (b) and (c)

Svetach [21]

Answer:

7 (this is most likely wrong i just needed to do this to make my account I am very sorry)

8 0

3 years ago

Martha has 30 cakes

Rashid [163]

Marta has 17/30 of the cakes left

3 0

3 years ago

What does 22.6−12.286−3.542 equal?

Lelechka [254]

Answer: Your answer is 6.772

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

Pumping stations deliver oil at the rate modeled by the function D, given by d of t equals the quotient of 5 times t and the qua

goblinko [34]

<h2>Hello!</h2>

The answer is: There is a total of 5.797 gallons pumped during the given period.

To solve this equation, we need to integrate the function at the given period (from t=0 to t=4)

The given function is:

$D(t)=\frac{5t}{1+3t}$

So, the integral will be:

$\int\limits^4_0 {\frac{5t}{1+3t}} \ dx$

So, integrating we have:

$\int\limits^4_0 {\frac{5t}{1+3t}} \ dt=5\int\limits^4_0 {\frac{t}{1+3t}} \ dx$

Performing a change of variable, we have:

$1+t=u\\du=1+3t=3dt\\x=\frac{u-1}{3}$

Then, substituting, we have:

$\frac{5}{3}*\frac{1}{3}\int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du\\\\\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u}{u} -\frac{1}{u } \ du$

$\frac{5}{9} \int\limits^4_0 {(\frac{u}{u} -\frac{1}{u } )\ du=\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u } )$

$\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u })\ du=\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du$

$\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du=\frac{5}{9} (u-lnu)/[0,4]$

Reverting the change of variable, we have:

$\frac{5}{9} (u-lnu)/[0,4]=\frac{5}{9}((1+3t)-ln(1+3t))/[0,4]$

Then, evaluating we have:

$\frac{5}{9}((1+3t)-ln(1+3t))[0,4]=(\frac{5}{9}((1+3(4)-ln(1+3(4)))-(\frac{5}{9}((1+3(0)-ln(1+3(0)))=\frac{5}{9}(10.435)-\frac{5}{9}(1)=5.797$

So, there is a total of 5.797 gallons pumped during the given period.

Have a nice day!

4 0

3 years ago

A light bulb filament is one-hundredth of an inch thick, with an allowable error of 2 percent. What is the least allowable thick

Andreyy89

Answer:

0.00998 Inches

Step-by-step explanation:

Thickness of the light bulb filament = 0.01 Inch

Allowable error = 2%.

2% of 0.01 = 0.02 X 0.01 =0.0002 Inch

Therefore, the allowable thickness of the bulb filament

$=0.01 \pm 0.0002 $ Inches$

We can then calculate the least allowable thickness of the filament as:

$=0.01 - 0.0002 \\=0.00998$ Inches$

The least allowable thickness of the filament is 0.00998 Inches.

3 0

4 years ago