Answer:
(√2 - √6) / 4
C. square root of two minus square root of six divided by four.
Step-by-step explanation:
sine of negative eleven pi divided by twelve.
We have :
sin(-11π/12)
sin((4 - 15)π / 12) = sin(4π/12 - 15π/12)
sin(4π/12 - 15π/12) = sin(π/3 - 5π/4)
Recall:
Angle difference formula:
sin(A - B) = sinAcosB - sinBcosA
Hence,
sin(π/3 - 5π/4) = sin(π/3) cos(5π/4) − sin(5π/4) cos(π/3)
From trigonometry:
sinπ/3 = √3/2
cos5π/4 = -√2/2
sin5π/4 = -√2/2
cos π/3 = 1/2
(√3/2) (-√2/2) − (-√2/2) (1/2)
-√6/4 - -√2/4
-√6/4 + √2/4
√2/4 - √6/4
(√2 - √6) / 4
Add all of them and them subtract by the value
Answer:
what? what is this supposed to be?
