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KatRina [158]
3 years ago
14

Help helppp pls math

Mathematics
2 answers:
andrey2020 [161]3 years ago
7 0

\angle1 = 60 °\\ \angle2 = 30° \\ \angle3 = 150°

mariarad [96]3 years ago
5 0

the correct answers are

<1=60

<2=30

<3=150

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Simplify 3 squared 2 ⋅ 3 squared 5
Mnenie [13.5K]

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45

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Can someone PLEASE help me!! I'm doing a test and I'm really stuck of this question! Each of the small squares in the figure bel
Arturiano [62]

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40 meters²

Step-by-step explanation:

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What is x in x + 4 = -x - 4
VashaNatasha [74]

Answer: -4

Step-by-step explanation:

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3 years ago
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The probability that a lab specimen contains high levels of contamination is 0.14. A group of 4 independent samples are checked.
Shtirlitz [24]

Answer:

a) 0.5470 = 54.70% probability that none contain high levels of contamination.

b) 0.3562 = 35.62% probability that exactly one contains high levels of contamination.

c) 0.4530 = 45.30% probability that at least one contains high levels of contamination.

Step-by-step explanation:

For each sample, there are only two possible outcomes. Either they contain high levels of contamination, or they do not. The samples are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that a lab specimen contains high levels of contamination is 0.14.

This means that p = 0.14

A group of 4 independent samples are checked.

This means that n = 4

(a) What is the probability that none contain high levels of contamination?

This is P(X = 0)

P(X = 0) = C_{4,0}.(0.14)^{0}.(0.86)^{4} = 0.5470

0.5470 = 54.70% probability that none contain high levels of contamination.

(b) What is the probability that exactly one contains high levels of contamination?

This is P(X = 1)

P(X = 1) = C_{4,1}.(0.14)^{1}.(0.86)^{3} = 0.3562

0.3562 = 35.62% probability that exactly one contains high levels of contamination.

(c) What is the probability that at least one contains high levels of contamination?

Either none of the samples contain high levels of contamination, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want to find P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.5470 = 0.4530

0.4530 = 45.30% probability that at least one contains high levels of contamination.

8 0
3 years ago
Will give brainliest and 50 points
mr_godi [17]

when you divide -8/2=-4 and 2/2=1

-4<1

when you divide by a negative number your sign changes

4>-1

When you multiply or divide each side by 2, the signs stay the same. −16 < 4 and −4 < 1. When you multiply or divide by −2, the inequality sign reverses. 16 > −4 and 4 > −1.

5 0
3 years ago
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