You bought a new car for $15,000 and know that it loses 1 5 of its value every year. The equation that models the value of your
car is y = 15000( 4 5 )x. Which is the MOST reasonable domain for this function?
2 answers:
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Answer:
The three angles of the triangle are 90, 35.67 and 54.33 degrees.
Step-by-step explanation:
One way to find the angles of the triangle with vertices (1, 1, 1), (1, -3, 2), (-3, 2, 5) is using the definition of the <em>dot product</em> of two vectors, defined as:
a . b = |a| |b| cosФ [1]
Where |a| and |b| are the norms of vectors <em>a</em> and b, and cosФ is the cosine of the angle between either vector <em>a</em> and <em>b</em>.
If a = [ ] and b = [
], then the dot product is simply a number (not a vector) obtained from:
a . b =
The norm of a vector (its length) is, for instance, |a| = , for a vector in
.
Having all that into account, we can determine the angles of the triangle for each vertex using equation [1] and solving it for Ф.
<h3>Angle of the triangle for vertex in (1, 1, 1)</h3>The vectors which form an angle from this vertex are the result of subtracting the vertex (1, 1, 1) to any of the remaining points (1, -3, 2) and (-3, 2, 5):
v(1, 1, 1) - v(1, -3, 2) =
v(1, 1, 1) - v(-3, 2, 5) =
The <em>dot product</em> for these vectors is:
[0, 4, -1] . [4, -1, -4] = [0 * 4 + 4 * -1 + -1 * -4] = 0 - 4 + 4 = 0
The norm for each vector is:
|(0, 4, -1)| =
|(4, -1, -4)| =
So
a . b = |a| |b| cosФ
In vertex (1, 1, 1) the angle of the triangle is 90 degrees. We have here a right triangle.
We have to follow the same procedure for finding the vectors for angles in vertices (1, -3, 2) and (-3, 2, 5), or better, after finding one of the previous angles, we find the remaining angle subtracting the sum of two angles from 180 degrees to finally obtaining the three angles in question.
Therefore, the other angles are 35.67 degrees and 180 - (90 + 35.67) = 180 - 125.67 = 54.33 degrees.
<u>Corrected Question</u>
Ping lives at the corner of 3rd Street and 6th Avenue. Ari lives at the corner of 21st Street and 18th Avenue. There is a gym 2/3 the distance from Ping's home to Ari's home. Where is the gym?
- 9th Street and 10th Avenue
- 12th Street and 12th Avenue
- 14th Street and 12th Avenue
- 15th Street and 14th Avenue
Answer:
(D)15th Street and 14th Avenue
Step-by-step explanation:
Ping's Location: (3rd Street, 6th Avenue)
Ari's Location: (21st Street, 18th Avenue)
The gym is at point P which is the distance from Ping's home to Ari's home.
That is, Point P divides the line segment in the ratio 2:1.
We use the section formula:
m:n=2:1,
The gym is located at 15th Street and 14th Avenue.