I graphed it. First you choose a number that’s less than 29 and greater than 29 which I chose 0 and 100 but it didn’t let me show the whole picture
Answer:
2556
Step-by-step explanation:
We put this into an algebraic equation, where <span>x = the number .
x + 17 > 26
x > 9
This </span>> is the greater than sign, we use this because it's no less than 26.
Ideally we would use this sign:
<span>http://etc.usf.edu/clipart/41700/41712/fc_greateq_41712_md.gif
because it could be equal to 26.
</span><span>The number is <u>greater or equal to 9</u>
</span>
Let u=x^3
the original equation becomes: u^2-9u+8=0
factor this quadratic equation: (u-8)(u-1)=0
u=8, or u=1
that means x^3=8 or x^3=1
x=2 x=1
Answer:
56
Step-by-step explanation:
If there can be only one 1 and only one 2, the remaining digits must all be 0. The digits 1 and 2 can be anywhere in the 8 digits, and can be in either order.
There are 8 possible locations in the sequence for the 1, then 7 possible locations for the 2. The total number of possibilities is 8·7 = 56.
12000000, 21000000, 10200000, 20100000, ..., 00000012, 00000021.
