This problem Is an example of geometrica progression. The formula
for the sum of geometric progression is:
S = a[(r^n)-1] / (r – 1)
Where s is the sum
a is the first term = 1
r is the common ratio = 2 ( because it doubles every year
n is the number of terms = (19) since the first term is when
he was born which he still 0
s = S = 1[(2^19)-1] / (2 – 1)
s = $524,287
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The sample space would be the number of students, so 1200.
The outcome the compose the event would be drawing one name at random.
The probability of Sophia winning would be 1 out of 1200, as a fraction: 1/1200, as a decimal: 0.00083
Because there is 1200 students, the probablity would be unlikely, since the sample is a large number.
Answer:
1/3
Step-by-step explanation:
Assuming that both die are labelled 1 - 6, the successful outcomes are 3 and 5 or 3 and 6. This is 2 out of the 6 possible outcomes so the answer is 2/6 or 1/3.
Yes, they are congruent. Congruent means that they are exactly equal in size and shape. The are both Right Triangles (you can tell by the 90 degree angle) and the lines on them are in the same spots, which means, line YZ is equal to line BC, and that line XZ is equal to line AC. I hope that helped! :)
