The surface area of a cylinder with circular bases of radius r and height h is equal to the sum of the areas of the two circular faces and the area of the rectangular lateral surface:

A = 2πr² + 2πrh

If you know the height h, then you can solve the quadratic equation for r.

7 0

3 years ago

If f(x) = 2x2 + 1 and g(x) = x2 – 7, find (f – g)(x).

nadya68 [22]

Answer: The required value is

$(f-g)(x)=x^2+8.$

Step-by-step explanation: The given functions are:

$f(x)=2x^2+1,\\\\g(x)=x^2-7.$

We are given to find the value of $(f-g)(x).$

We know that, if s(x) and t(x) are any two functions of a variable x, then we have

$(s-t)(x)=s(x)-t(x).$

Therefore, we have

$(f-g)(x)\\\\=f(x)-g(x)\\\\=(2x^2+1)-(x^2-7)\\\\=2x^2+1-x^2+7\\\\=x^2+8.$

Thus, the required value is

$(f-g)(x)=x^2+8.$

5 0

3 years ago

Janine graphs these two lines and finds that they intersect.

Hunter-Best [27]

Answer:3

Step-by-step explanation:

5 0

2 years ago