For 2 1/6 = 13/6 Ft, ant takes = 1 min.
So, for 1 ft, it takes = 6/13 min.
Now, for 5 1/5 = 26/5 min. it would take = 6/13 * 26/512/5 = 2.4 min
In short, Your Answer would be 2.4 min
Hope this helps!
That's not true. 56 is 10 more than 46. 46 +10 is 56.
If these are the missing choices:
A) Segments ST and PQ are parallel.
B) Angle P is congruent to itself due to the reflexive property.
C) RP is a transversal line passing ST and PQ.
<span>D) Angles RTS and RQP are congruent due to the Corresponding Angles Postulate.
</span>The fact that is not used to prove that PQR is similar to STR is <span>B) Angle P is congruent to itself due to the reflexive property.
</span>
Reflexive property in the given image is on Angle R not angle P.
Answer:
Step-by-step explanation:
You need to remember the mulplication of signs:
Knowing this, you can distributive the negative sign. Then you get:
Now you need to add the like terms. Then:
Finally, you can order the polynomial obtained in descending order. Therefore, the answer is:
<span>(1 + cos² 3θ) / (sin² 3θ) = 2 csc² 3θ - 1
Starting with the left: Note that cos²θ + </span><span>sin²θ = 1.
In the same way: </span><span>cos²3θ + <span>sin²3θ = 1
</span></span>Therefore cos²3θ = 1 - <span>sin²3θ
</span> From the top: (1 + cos² 3θ) = 1 + 1 - sin²3θ = 2 - <span>sin²3θ
</span>
(1 + cos² 3θ) / (sin² 3θ) = (<span>2 - sin²3θ) / (sin² 3θ) = 2/</span><span>sin² 3θ - </span><span>sin²3θ/</span>sin²3θ
= 2/<span>sin² 3θ - 1; But 1/</span><span>sinθ = csc</span><span>θ, Similarly </span>1/sin3θ = csc3θ
= 2 *(1/sin<span>3θ)² - 1</span>
= 2csc²3θ - 1. Therefore LHS = RHS. QED.