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vazorg [7]
3 years ago
9

Rectangle ABCD is rotated 90 degrees. Which statment below is true? a. The image is one half the size of the rpe image. b. The a

ngle measurements of the image are one half the angle measurements of the pre-image. c. The image is the same size and same shape. d. The image is the same size but a different shape
Mathematics
1 answer:
geniusboy [140]3 years ago
4 0
Ive answered this already 
Its c  Rotation does not chamge shape or size.
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Please help ASAP!!!!!
Margaret [11]

Answer:

The answer is -14/25 or - 0.56

5 0
3 years ago
How much does 6.1 cubic feet of water weigh in pounds
Dovator [93]

Answer:

380.832 pounds    Approximately

Step-by-step explanation:

1 foot of water = 62.428 pounds  (62.43)

6.1* 62.43= 380.832

6 0
3 years ago
Which of the following values of x will result in a true statement when
vodka [1.7K]

Answer:

Step-by-step explanation:

Here you go mate

Use PEMDAS

Parenthesis

Exponent

Multiplication

Division

Addition

Subtraction

Step 1

-3(x-2)=9  Equation/Question

Step 2

-3(x-2)=9  Remove parenthesis

3x+6=9

Step 3

3x+6=9  Add -6

-3x=3

Step 4

−3x=3  Divide

answer

x=-1

Hope this helps

5 0
3 years ago
Basic Algebra problem....
kompoz [17]

Answer:

2*2*3*3

Step-by-step explanation:

36 is a composite number and it 6 squared. As such, it can be factorized completely as:

36=2\times 2\times3 \times 3

Hence, the factored form of 36 is 2x2x3x3

5 0
3 years ago
The graph of y = f(x) is shown. Choose all the true statements.
dexar [7]

Answer:

−2 is a member of the domain of f.

f(0) > 0

Step-by-step explanation:

Statement 1 is TRUE. Domain value includes set of values of x of the function. -2 is plotted on the x-axis on the graph. Therefore, it is a member of domain of f.

Statement 2 is incorrect. Range includes all possible y-values of the function. On the graph, no y-value plotted is -2. Therefore, -2 is NOT a member of the range of f.

Statement 3 is TRUE.

f(0) is approximately 2.2 on the graph. i.e. at x = 0, y ≈ 2.2.

Therefore, f(0) > 0.

Statement 4 is INCORRECT.

f(2) = 1, that is at x = 2, y = 1 as seen in the graph. Therefore, f(2) is not greater than 2.

8 0
4 years ago
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