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3 years ago

How to put one hundred forty one million six hundred twenty thousand in standard form

Mathematics

2 answers:

Brums [2.3K]3 years ago

6 0

Answer:

140,620,000

Step-by-step explanation:

There are two types of standard form. The one above (given to you) is the normal standard form. However, there is another one. This one would look like:

140,620,000 = 1.4062 x 10^8

Remember that in this standard form, you must move the decimal to just after the first place value, and the amount of moves you made for the decimal is the amount in the power over 10.

Ksivusya [100]3 years ago

5 0

Answer: 141,620,000

you have to put each number in its place the 141 in the millions places the 620 in the thousands places and the 0's in the ones tens and hundred places.

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Jamie need to earn more than $4,000 to pa his monthly bills. he earns a monthly salary of $2,500 plus an extra $75 for every ele

Black_prince [1.1K]

Answer:

Step-by-step explanation:

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3 years ago

Write the equation of the line that is parallel to y=4x-3 and passes through the point (5,12)

katovenus [111]

Answer

y=4x-8

Step-by-step explanation:

m = 4

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simplify and keep it in point-slop form

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3 years ago

For the following telescoping series, find a formula for the nth term of the sequence of partial sums

gtnhenbr [62]

I'm guessing the sum is supposed to be

$\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}$

Split the summand into partial fractions:

$\dfrac1{(5k-1)(5k+4)}=\dfrac a{5k-1}+\dfrac b{5k+4}$

$1=a(5k+4)+b(5k-1)$

If $k=-\frac45$ , then

$1=b(-4-1)\implies b=-\frac15$

If $k=\frac15$ , then

$1=a(1+4)\implies a=\frac15$

This means

$\dfrac{10}{(5k-1)(5k+4)}=\dfrac2{5k-1}-\dfrac2{5k+4}$

Consider the $n$ th partial sum of the series:

$S_n=2\left(\dfrac14-\dfrac19\right)+2\left(\dfrac19-\dfrac1{14}\right)+2\left(\dfrac1{14}-\dfrac1{19}\right)+\cdots+2\left(\dfrac1{5n-1}-\dfrac1{5n+4}\right)$

The sum telescopes so that

$S_n=\dfrac2{14}-\dfrac2{5n+4}$

and as $n\to\infty$ , the second term vanishes and leaves us with

$\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}=\lim_{n\to\infty}S_n=\frac17$

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3 years ago

A circle has a radius of five ft.

Flura [38]

A. for the circumference it is C=pi(d)=pi(2r)=pi(10)= 31.4 ft
b. for the area it is A=pi(r)^2=pi(5)^2=pi(25)= 78.5 ft squared
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3 years ago

A piece of wood is cut into 3 pieces in the ratio 5:4:3 if the length of the shortest piece is 2 how long is the wood

Bad White [126]

Answer:

Step-by-step explanation:

5:4:3 = x:y:2

4:3 = y:2 Cross multiply

3y = 8 Divide by 3

y = 8/3 = 2.66'

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x = 10/3

x = 3.33

Length of the wood = 2.66 + 3.33 + 2

Length of the wood = 8 feet

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3 years ago