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nignag [31]
3 years ago
15

BRAINLIEST!!

Mathematics
2 answers:
Sunny_sXe [5.5K]3 years ago
8 0
Hey we are doing the same thing in school but if you're trying to find the probability of it being less than 5 you would have 4,3,2,1. so you would have 4 numbers which would be 4/6. simplified it would be 2/3.
Viktor [21]3 years ago
4 0
There are 6 sides, with 6 numbers. A number less than 5 is 4/6, or simplified, 2/3.
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Ahhhh help everyone help me solve this ....​
vovangra [49]

Answer:

y =  \frac{18 {w}^{2}  {x}^{2}  {z}^{2} }{25}

Step-by-step explanation:

\frac{3wx}{ \sqrt{2y} }  =  \frac{5}{2z}  \\  \\  \sqrt{2y}  \times 5 = 3wx \times 2z \\  \\  \sqrt{2y}   \times 5 = 6wxz \\  \\  \sqrt{2y}  =  \frac{6wxz}{5}  \\  \\  {( \sqrt{2y} })^{2}  =  {( \frac{6wxz}{5} })^{2}  \\  \\ 2y =  \frac{36 {w}^{2} {x}^{2} {z}^{2}   }{25}  \\  \\  \\  y =  \frac{36 {w}^{2} {x}^{2}  {z}^{2}  }{25}  \div 2 \\  \\  \\ y =  \frac{36 {w}^{2} {x}^{2} {z}^{2}   }{25}  \times  \frac{1}{2}  \\  \\  \\ y =  \frac{36 {w}^{2} {x}^{2}  {z}^{2}  }{50}  \\  \\  \\ y =  \frac{18 {w}^{2} {x}^{2}   {z}^{2} }{25}

I hope I helped you^_^

4 0
3 years ago
Find the LCM of the numbers using prime factorizations. 36,60
alexandr402 [8]
36=2*2*3*3=2²*3²
60=2*2*3*5=2²*3*5

LCM(36,60)=2*2*3*3*5=2²*3²*5=180
5 0
2 years ago
A number is multiplied by 5. If 12 is added to the product you get 37.
Korolek [52]


5x+12=37

5x=25

x=5

I hope this helps


5 0
3 years ago
The parents club wants to sell buttons to raise money for the local community center sports program. The buttons cost 60 cents e
astraxan [27]

Their profit made will be 4,420

This is because 0.60 x 1300 is 780

And the amount they will make by selling is $5200, because 1300 x 4

So we will do 5200 - 780, and that is the profit made- $4,420

3 0
3 years ago
Read 2 more answers
1. There are 78 sophomores at a school. Each is required to take at least one year of either chemistry or physics, but they may
SVETLANKA909090 [29]

We are given that there are a total of 78 students. If we set the following variables:

\begin{gathered} C=\text{students only in chemestry} \\ P=\text{students only in physics} \\ PC=\text{students in physics and chemistry} \end{gathered}

Then, the sum of all of these must be 78, that is:

C+P+PC=78

Since there are 15 in chemistry and physics and 47 in chemistry, we may replace that into the equation and we get:

47+P+15=78

Simplifying:

62+P=78

Now we solve for P by subtracting 62 on both sides:

\begin{gathered} 62-62+P=78-62 \\ P=16 \end{gathered}

Therefore, there are 16 students in physics

3 0
1 year ago
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