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Molodets [167]
2 years ago
12

Determinar la longitud de la hipotenusa del siguiente triángulo si se conocen las medidas que se indican de los demás triángulos

.

Mathematics
1 answer:
Zina [86]2 years ago
3 0

it helps a lot in math us it won't let me do it

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5 and 4 sevenths times negative 2 and 2 fifths
Dimas [21]

Answer:

3/2

Step-by-step explanation:

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PLEASE HELP I CANT UNDERSTAND I NEED HELP
Vika [28.1K]

Answer:

Count houw many boxes the linegoes over

Step-by-step explanation:

7 0
2 years ago
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I don't know if this is right... please someone help mee
worty [1.4K]
For the first circle, let's use the pythagorean theorem

\bf \textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{8^2+15^2}\implies c=\sqrt{289}\implies c=17

now, it just so happen that the hypotenuse on that triangle, is actually 17, but we used the pythagorean theorem to find it, and the pythagorean theorem only works for right-triangles.

 so if the hypotenuse is actually 17, that means that triangle there is actually a right-triangle, meaning that the radius there, and the outside line there, are both meeting at a right-angle.

when an outside line touches the radius line, and they form a right-angle, the outside line is indeed a tangent line, since the point of tangency is always a right-angle with the radius.



now, let's check for second circle

\bf \textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{11^2+14^2}\implies c=\sqrt{317}\implies c\approx 17.8044938

well, low and behold, we didn't get our hypotenuse as 16 after all, meaning, that triangle is NOT a right-triangle, and that outside line is not touching the radius at a right-angle, therefore is NOT a tangent line.



let's check the third circle

\bf \textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{33^2+56^2}\implies c=\sqrt{4225}\implies c=\stackrel{33+32}{65}

this time, we did get our hypotenuse to 65, the triangle is a right-triangle, so the outside line is indeed a tangent line.
6 0
2 years ago
What is 1/5 ÷ 5<br> someone pls help me
Elena-2011 [213]

Answer: 1/25 or 0.04

Step-by-step explanation:

1/5 divided by 5 for the whole number you have to turn it to a fraction so you would do 5/1

THEN: it becomes 1/5 divided by 5/1 but you have to do the inverse so the inverse of division is multiplying and you will cross multiply so 5*5= 25 and 1*1=1 therefor the final answer is 1/25

5 0
2 years ago
Read 2 more answers
Find the slope between the points (3,2) and (4,1) *
Tpy6a [65]

Answer:

-1/1 or -1

Step-by-step explanation:

subtract y: 3-4= -1

subtract x: 2-1=1

answer: -1/1

3 0
2 years ago
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