The complete version of question:
<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>
Answer:
Step-by-step explanation:
As the description of the statement is:
'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>
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As
- <em>Five times the sum of a number and 27 </em>is written as:

- <em>greater than or equal </em>is written as:

- <em>six times the sum of that number and 26' </em>is written as: 6(x + 26)
so lets combine the whole statement:
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solving
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Therefore,
Answer:
The length of AC is 10 units
Step-by-step explanation:
In the given circle O
∵ AOCB is a rectangle
∵ OB and AC are the diagonals of the rectangle AOCB
∵ Diagonals of the rectangle are equal in lengths
→ That means OB and AC are equal in lengths
∴ OB = AC
∵ O is the center of the circle
∵ B is a point on the circle
∴ OB is a radius of the circle O
∵ The radius of the circle is 10 units
∴ OB = 10 units
∵ OB = AC
∴ AC = 10 units
∴ The length of AC is 10 units
Answer:
12.5
10
Step-by-step explanation:
10(1/2+3/4)
5+7.5
12.5
10(1/2)+(8(3/4)-1)
5+(6-1)
5+5
10
A number 4 times as much as 25 is 100
Answer:
C. -2.5 - 6.5n
Step-by-step explanation:
i just think thats the answer