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Natalija [7]
3 years ago
14

Maria is comparing the prices of two window cleaning companies. Company A charges $6 per window and an additional $12 as service

charges. Company B charges $5 per window and an additional $15 as service charges. Part A: Write equations to represent Company A's and Company B's total charges for cleaning a certain number of windows. Define the variable used in the equations. (4 points) Part B: Which company would charge less for cleaning 8 windows? Justify your answer. (3 points) Part C: How much money is saved by using the services of Company B instead of Company A to clean 6 windows? (3 points) (10 points)
Mathematics
2 answers:
rewona [7]3 years ago
8 0
Part A Answer: Company A: (Wx6)+12 Company B: (Wx5)+15 The varible used was W because windows start with a W i chose this as the variable because it is for the certain NUMBER of windows. Part B:Company A: 8x6=48+12=$70 for 8 windows and service charges. Company B:8x5=40+15=$55 for 8 windows and service charges. Company B would charge less for 8 windows. Part C:My work for Company A: 6x6=36+12=$48 for 6 windows and service charges My work for Company B: 6x5=30+15=$45 for 6 windows + service charges $48-$45=$3 Answer for Part C: $3 would be saved by using the services of Company B instead if Company A to clean 6 windows.
finlep [7]3 years ago
6 0
<h2>Answer:</h2>

Part A:

Let 'x' be the number of windows cleaned.

Let 'y' be the total cost of cleaning 'x' windows.

Company A charges $6 per window and an additional $12 as service charges. So equation becomes y=6x+12

Company B charges $5 per window and an additional $15 as service charges. So equation becomes y=5x+15

Part B :

Cost for cleaning 8 windows.

Company A = y=6(8)+12 =$60

Company B = y=5(8)+15 =$55

Company B charges less for 8 windows.

Part C:

Cost for cleaning 6 windows.

Company A = y=6(6)+12 =$48

Company B = y=5(6)+15 =$45

Money saved by using company B is 48-45=3 dollars.

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ale4655 [162]

Answer:

70 hope it helps

Step-by-step explanation:

210/3=70

5 0
2 years ago
8. How much energy does a 12 V battery in your car use to move 2.5 C through the electrical
I am Lyosha [343]

The energy required is 30 watts second.

In order to accomplish work and to produce heat and light, energy must be transferred to a body or to a physical system. Energy is the quantitative attribute that does this. Energy is a preserved resource; according to the rule of conservation of energy, energy can only be transformed from one form to another and cannot be created or eliminated.

The voltage of a battery is 12 V and;

The charge is 2.5C.

Now, energy can be defined as the product of voltage and charge.

Therefore,

E = V × C

E = 12 × 2.5

E = 30 watt second

Hence, the energy needed by the 12 V battery to move 2.5 C through the electrical circuit is 30 watts second.

Learn more about energy here:

brainly.com/question/13881533

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6 0
1 year ago
Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y
irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

y'(x)= x^2y(x)-\frac12y^2(x)

Putting the value of y'(x) in equation (1)

y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))

Substituting x =0 and h= 0.2

y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]

\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]    [∵ y(0) =3 ]

\Rightarrow y(0.2)\approx 2.7

Substituting x =0.2 and h= 0.2

y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]

\Rightarrow y(0.4)\approx  2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]

\Rightarrow y(0.4)\approx 1.9926

Substituting x =0.4 and h= 0.2

y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]

\Rightarrow y(0.6)\approx  1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]

\Rightarrow y(0.6)\approx 1.6593

Substituting x =0.6 and h= 0.2

y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]

\Rightarrow y(0.8)\approx  1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]

\Rightarrow y(0.6)\approx 0.8800

Substituting x =0.8 and h= 0.2

y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]

\Rightarrow y(1.0)\approx  0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]

\Rightarrow y(1.0)\approx 0.9152

Therefore the value of y(1)= 0.9152.

4 0
3 years ago
Al has twice as many cards as Bob, and Jane has three times as many cards as Bob. Together, they have 372 cards. How many cards
Musya8 [376]

Answer: Bob has 62 cards.

All has 124 cards.

Jane has 186 cards

Step-by-step explanation:

Let x represent the number of cards that Bob has.

Al has twice as many cards as Bob. It means that the number of cards that All has is 2x.

Jane has three times as many cards as Bob. It means that the number of cards that Jane has is 3x.

Together, they have 372 cards. It means that

x + 2x + 3x = 372

6x = 372

x = 372/6

x = 62

The number of cards that Al has is

2 × 62 = 124

The number of cards that Jane has is

3 × 62 = 186

8 0
3 years ago
What is the greatest common factor of 42 ab 35ab4 and 42ab42
Lana71 [14]

Answer:

7

Step-by-step explanation:

6 0
3 years ago
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