Lawrence's is the correct answer. he put 3 plates on each box in both situations
Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
In this problem, the mean and the standard deviation are given, respectively, by:
.
The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:


Z = 1.71
Z = 1.71 has a p-value of 0.9564.
1 - 0.9564 = 0.0436.
0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.
More can be learned about the normal distribution at brainly.com/question/24663213
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Answer:
284.72
Step-by-step explanation:
there you go
Answer:
I disagree with the other answer.
Step-by-step explanation:
The reason for this is because if you have 12/32 for team 1, and 15/35 on team 2, then you do cross products(a type of shortcut).
12/32 15/35
1) Multiply 12 and 35= 420
2) Multiply 15 and 32= 480
3) Which number is greater?
<u>Answer</u>
<em>TEAM 2</em>..(or the visiting team)