THIS IS THE COMPLETE QUESTION BELOW;
The weekly salaries of sociologists in the United States are normally distributed and have a known population standard deviation of 425 dollars and an unknown population mean. A random sample of 22 sociologists is taken and gives a sample mean of 1520 dollars.
Find the margin of error for the confidence interval for the population mean with a 98% confidence level.
z0.10 z0.05 z0.025 z0.01 z0.005
1.282 1.645 1.960 2.326 2.576
You may use a calculator or the common z values above. Round the final answer to two decimal places.
Answer
Margin error =210.8
Given:
standard deviation of 425
sample mean x=1520 dollars.
random sample n= 22
From the question We need to to calculate the margin of error for the confidence interval for the population mean .
CHECK THE ATTACHMENT FOR DETAILED EXPLANATION
It's reflection; it's not translation
so answer is the last one.
d. No; it is one reflection after another with respect to the two parallel lines.
hope it helps
1 centimeter is equivalent to 10 millimeters. So 15x10=150 millimeters.
Hope this helped! :D
Answer:
Step-by-step explanation:
-3 = 2x+6y
2x+6y = 0
By transitivity, -3 = 0, a contradiction. No solution.
If you graph the lines, you will see they are parallel, therefore never intersect.