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blsea [12.9K]
3 years ago
7

Dward has four pearls – two white and two black – which he can distribute as he chooses between two identical bags. He must then

choose a bag at random and pick one pearl at random from the bag he chose. If Edward distributes the pearls so as to maximize his chances of pulling a black pearl, what is the probability that Edward will pick a black pearl?
A. 1/2
B. 3/5
C. 2/3
D. 3/4
E. 1
Mathematics
1 answer:
Annette [7]3 years ago
8 0

Answer:

Answer is 3/4

Step-by-step explanation:

Edward can distrubute pearls to 2 identical bags as fallows:

  • 2W for one bag and 2B for another bag. In this scenerio the probability of picking a black pearl is 1/2.
  • 1W and 1B for one bag and 1W and 1B for another bag. In this situation the probability of picking a black pearl is 1/2 × 1/2 is equal to 1/4
  • At the end, the sum of two scenerio is 1/2 + 1/4 = 3/4
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find the equation of a circle which passes through the point (2,-2) and (3,4) and whose centre lies on the line x+y=2
Nadusha1986 [10]

Answer:

Equation of the circle

(x - 0.7)² + (y - 1.3)² = 12.58

Step-by-step explanation:

The formula for the equation of a circle is given as:

(x - a)² + (y - b)² = r²,

where(a, b) is the center of the circle and r = radius of the circle.

a) We are told in the question that the equation of the circle passes through point(2, -2)

Hence,

Substituting 2 for x and -2 for y in the equation of the circle.

(x - a)² + (y - b)² = r²

(2 - a)² +(-2 - b)² = r²

Expanding the bracket

(2 - a) (2 - a) + (-2 - b)(-2 - b) = r²

4 - 2a - 2a +a² +4 +2b +2b +b² = r²

4 - 4a + a² + 4 + 4b + b² = r²

a² + b² -4a + 4b + 4 + 4 = r²

a² + b² -4a + 4b + 8 = r²............Equation 1

We are also told that the equation of the circle also passes through point (3,4) also, where 3 = x and 4 = y

Hence,

Substituting 3 for x and 4 for y in the equation of the circle.

(x - a)² + (y - b)² = r²

(3 - a)² +(4 - b)² = r²

Expanding the bracket

(3 - a) (3 - a) + (4 - b)(4- b) = r²

9 - 3a - 3a +a² +16 -4b -4b +b² = r²

9 -6a + a² + 16 -8b + b² = r²

a² + b² -6a -8b + 9 + 16 = r²

a² + b² -6a -8b + 25 = r²..........Equation 2

The next step would be to subtract Equation 1 from Equation 2

a² + b² -4a + 4b + 8 - (a² + b² -6a -8b + 25) = r² - r²

a² + b² -4a + 4b + 8 - a² - b² +6a +8b - -25= r² - r²

Collecting like terms

a² - a² + b² - b² - 4a + 6a + 4b + 8b +8- 25 = 0

2a + 12b -17 = 0

2a + 12b = 17...........Equation 3

Step 2

We are going to have to find the values of a and b in other to get our equation of the circle.

Since the center of the circle(a, b) lies on x + y = 2

Therefore, we have

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Substituting 2 - b for a in

2(2 - b) + 12b = 17

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4 + 10b = 17

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b = 1.3

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Step 3

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(x - a)² + (y - b)² = r²

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