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Over [174]
3 years ago
8

Write an equation of the ellipse with foci at (0,+12) and vertices at (0,+13)

Mathematics
2 answers:
Korolek [52]3 years ago
7 0

Quadratic relations and comic sections unit test part 1

10. b. x^2/25 + y^2/169 =1

nekit [7.7K]3 years ago
6 0
 To solve this problem you must apply the proccedure shown below:
 1. You have that the ellipse given as a vertical major axis (a=13), therefore, taking the ellipse with its center at the origin, you have the following equation:
 (y^2/a^2)+(x^2/b^2)=1
 2. You have the distance from the center of the ellipse to the focus:
 c=12, therefore, you can calculate the value of b, the minor radius:
 c^2=a^2-b^2
 b=√(13^3-12^2)
 b=5
 3. Therefore, the equation is:
 a^2=169
 b^2=25
 (y^2/169)+(x^2/25)=1
 The answer is: (y^2/169)+(x^2/25)=1 
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What is the math problem answer?
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To find the mid point add both X coordinates together and divide by 2 and then do the same with the y coordinates.

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3 0
3 years ago
3. At noon Lan is in his blue mini-van 300 km north of Makenna in her Bugatti. Lan heads south
LiRa [457]

Answer:

The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h

Step-by-step explanation:

At noon the location of Lan = 300 km north of Makenna

Lan's direction = South

Lan's speed = 60 km/h

Makenna's direction and speed = West at 75 km/h

The distance  Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km

The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km

The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km

Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.

By Pythagoras' theorem, we have;

s² = x² + y²

The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61

ds²/dt = dx²/dt + dy²/dt

2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt

2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900

ds/dt = 900/(2×30·√61) ≈ 1.92

The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h

5 0
3 years ago
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