Write an equation of the ellipse with foci at (0,+12) and vertices at (0,+13)

Mathematics

2 answers:

Korolek [52]3 years ago

7 0

Quadratic relations and comic sections unit test part 1

10. b. x^2/25 + y^2/169 =1

nekit [7.7K]3 years ago

6 0

To solve this problem you must apply the proccedure shown below:
1. You have that the ellipse given as a vertical major axis (a=13), therefore, taking the ellipse with its center at the origin, you have the following equation:
(y^2/a^2)+(x^2/b^2)=1
2. You have the distance from the center of the ellipse to the focus:
c=12, therefore, you can calculate the value of b, the minor radius:
c^2=a^2-b^2
b=√(13^3-12^2)
b=5
3. Therefore, the equation is:
a^2=169
b^2=25
(y^2/169)+(x^2/25)=1
The answer is: (y^2/169)+(x^2/25)=1

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