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ale4655 [162]
2 years ago
9

Select the correct answer.

Mathematics
2 answers:
Oduvanchick [21]2 years ago
6 0
I think answer should be thousands please give me brainlest I hope this helps let me know if it’s correct or not okay thanks
alexandr1967 [171]2 years ago
5 0
The correct name for the place that the digit 9 stands in is , one thousand .
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Name the vertex of angle 6.
amid [387]

Answer:

D

Step-by-step explanation:

∠ 6 is formed by the 2 lines that intersect at D

then the vertex of ∠ 6 is D

8 0
1 year ago
Which equation represents a circle that contains the point (-5, 3) and has a center at (-2, 1)? Distance formula: vaa -02 (x - 1
natali 33 [55]

Given:

The center of the circle = (-2,1).

Circle passes through the point (-5,3).

To find:

The equation of the circle.

Solution:

Radius is the distance between the center of the circle and any point on the circle. So, radius of the circle is the distance between the points (-2,1) and (-5,3).

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

r=\sqrt{(-5-(-2))^2+(3-1)^2}

r=\sqrt{(-5+2)^2+(2)^2}

r=\sqrt{(-3)^2+(2)^2}

On further simplification, we get

r=\sqrt{9+4}

r=\sqrt{13}

The standard form of a circle is:

(x-h)^2+(y-k)^2=r^2

Where, (h,k) is the center of the circle and r is the radius of the circle.

Substitute h=-2, k=1 and r=\sqrt{13}.

(x-(-2))^2+(y-1)^2=(\sqrt{13})^2

(x+2)^2+(y-1)^2=13

Therefore, the equation of the circle is (x+2)^2+(y-1)^2=13.

8 0
3 years ago
What is the value of the function at x=−3?<br><br> A) y = 0<br> B) y=−3<br> C) y = 4<br> D) y = 3
Alexus [3.1K]

Answer:

y=4

Step-by-step explanation:

From the graph we can see that-

when, x=-3 ,  y=4

That is , the graph passes through   (-3 , 4)

So,

for  x=-3 ,

we get    y=4

So, the answer is    y=4

5 0
3 years ago
What is the answer to <br> 1+38*225(12/77)
Neporo4naja [7]
1+38*225(12/77)
1+38*225*6.41
1*8550*6.41
1+54,805.5
54,806.5
Use pemdas to solve it
4 0
3 years ago
Read 2 more answers
Given the sequence 8, 12, 16, 20, 24, what is the sum of the 31st and 19th terms?
erica [24]

Answer:

First term (a) =8

Common difference (d)= t2-t1

=12-8

=4

Now, sum of first 31th term (tn31) =n/2{2a+(n-1)d}

= 31/2{2×8+(31-1)4}

=31/2{16+(30×4)

=31/2(16+120)

=31/2×126

=31×63

Step-by-step explanation:

Similarly use 19 as (n) for the 19th term

7 0
2 years ago
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