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The row echelon form of the matrix is presented as follows;
The row echelon form of a matrix has the rows consisting entirely of zeros at the bottom, and the first entry of a row that is not entirely zero is a one.
The given matrix is presented as follows;
The conditions of a matrix in the row echelon form are as follows;
- There are row having nonzero entries above the zero rows.
- The first nonzero entry in a nonzero row is a one.
- The location of the leading one in a nonzero row is to the left of the leading one in the next lower rows.
Dividing Row 1 by -3 gives:
Multiplying Row 1 by 2 and subtracting the result from Row 2 gives;
Subtracting Row 1 from Row 3 gives;
Adding Row 2 to Row 3 gives;
Dividing Row 2 by -2, and Row 3 by 18 gives;
The above matrix is in the row echelon form
Learn more about the row echelon form here:
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Answer:
0.75
Step-by-step explanation:
The table is not well presented (See Attachment)
There are at least two approaches to this question
Method 1:
Steps
1. Calculate the mean of reported heights
Mean of reported heights = (61+68+57.5+48.5+75+65+80+68+69+63)/10
Mean of reported heights = 655/10
Mean of reported heights = 65.5
2. Calculate the mean of measured heights
Mean of measured heights = (62 + 68 + 56.5 + 47 + 72 + 65 + 78 + 67 + 69.5 + 62.5)/10
Mean of measured heights = 647.5/10
Mean of measured heights = 64.75
3. Get their difference
Difference = Mean of reported heights - Mean of measured heights
Difference = 65.5 - 64.75
Difference = 0,75
Method 2: Calculate the mean of their difference
Mean of difference = Sum of difference / Number of observations
Mean of difference = (-1 + 0 + 1 + 1.5 + 3 + 0 + 2 + 1 – 0.5 + 0.5)/10
Mean of difference = 7.5/10
Mean of difference = 0.75
Note that in both cases, the result is 0,75.
Hence, the reported heights at the school is 0.75 greater than the actual measured height
