-x - 7y = 14 -4x - 14y = 28

A person who weighs 60 Kg on Earth where would 54 1/2 kilograms on Venus if a child weighs 25 3/4 Kg on Earth what would this ch

Flura [38]

Answer:

Weight On Venus: 22.60 kg

Step-by-step explanation:

Being that it takes the weight of an object on earth and converts it to the weight on Venus, <em><u>the formula</u></em> is Weight on Venus= (Weight on Earth/9.81m/s2) * 8.87m/s2. To find the weight on Venus, we divide the weight on earth by the earth's force of gravity, which is 9.81m/s2. This calculates the mass of the object. Once we have the object's mass, we can find the weight by multiplying it by the gravitational force, which it is subject to. Being that Venus has a gravitational force of 8.87m/s2, we multiply the object's mass by this quanitity to calculate an object's weight on Venus.

So an object or person on Venus would weigh 90.42% its weight on earth. Therefore, a person would be lighter on Venus than on earth. Conversely, a person is 9.58% heavier on earth than on Venus.

Venus is only 95% the size of Earth, and 81% of its mass. With the smaller size and mass, the force of gravity pulling you on the surface is lower. To get your weight on Venus, just multiply your current weight by 0.9. That's why 100 pounds becomes 90 pounds.

6 0

3 years ago

Read 2 more answers

The graph of f has the equation of f(x)=x^3-4x²-3x+18

Butoxors [25]

Hello,

y= x^3-4x²-3x+18=(x-3)²*(x+2)

y'=3x²-8x-3

y''=6x-8

1) Stationary points

Maximun: x=-1/3 ==>y=18,5185....
Minimum: x=3 ===>y=0 (double root)

2) x=4/3: point of inflection. (y''=0 and change sign)

5 0

3 years ago

To plan the budget for next year a college must update its estimate of the proportion of next year's freshmen class that will ne

Naily [24]

Answer:

Null hypothesis: $p\leq 0.35$

Alternative hypothesis: $p > 0.35$

$z=\frac{0.447 -0.35}{\sqrt{\frac{0.35(1-0.35)}{150}}}=2.491$

$p_v =P(z>2.491)=0.0064$

So the p value obtained was a very low value and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of applicants who request financial aid is significantly higher than 0.35

Step-by-step explanation:

Data given and notation

n=150 represent the random sample taken

X=67 represent the applicants who request financial aid

$\hat p=\frac{67}{150}=0.447$ estimated proportion of applicants who request financial aid

$p_o=0.35$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of applicants who request financial aid is higher than 0.35.:

Null hypothesis: $p\leq 0.35$

Alternative hypothesis: $p > 0.35$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.447 -0.35}{\sqrt{\frac{0.35(1-0.35)}{150}}}=2.491$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>2.491)=0.0064$

So the p value obtained was a very low value and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of applicants who request financial aid is significantly higher than 0.35

5 0

3 years ago

Please help me solve this

ASHA 777 [7]

Answer:

x>-1.5

Step-by-step explanation:

4 0

3 years ago

A microscope slide shows 37 red blood cells out of 60 blood cells . How many red blood cells would be expected in a sample of th

JulsSmile [24]

We know that there is a total of 900 cells, and 37 of the samples 60 are red. 900/60 is our unit rate of 15. 37 times 15 is 555. We will see 555 red blood cells in all of the cells.

555 is our answer.

Please forgive any typeos because I did this on my phone.

4 0

3 years ago