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ArbitrLikvidat [17]

2 years ago

5

PLEASE HELP DONT SKIP I NEED YOU

1 answer:

viva [34]2 years ago

6 0

Answer:

72 outfits possible,

1/72 chance of selecting a particular outfit

Step-by-step explanation:

For each of the 3 sweaters, there are 4 shirts to choose from, and for each of those 4 shirts, there are 6 pants to choose from. Therefore, there are totally $3\cdot 4\cdot 6=72$ outfits to choose from (order is fixed and therefore negligible). A specific outfit would represent 1 of these 72 outfits. Therefore, the probability of selecting a particular outfit is $\boxed{\frac{1}{72}}$

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