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ArbitrLikvidat [17]
3 years ago
5

PLEASE HELP DONT SKIP I NEED YOU

Mathematics
1 answer:
viva [34]3 years ago
6 0

Answer:

72 outfits possible,

1/72 chance of selecting a particular outfit

Step-by-step explanation:

For each of the 3 sweaters, there are 4 shirts to choose from, and for each of those 4 shirts, there are 6 pants to choose from. Therefore, there are totally 3\cdot 4\cdot 6=72 outfits to choose from (order is fixed and therefore negligible). A specific outfit would represent 1 of these 72 outfits. Therefore, the probability of selecting a particular outfit is \boxed{\frac{1}{72}}

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Z-m=z+bx , solve for b
KIM [24]

Answer:

b= (Z-m-z)/(x)

Step-by-step explanation:

Z-m=z+bx

Z-m-z=bx [Transpose z of R.H.S to L.H.S] / [Substract z from L.H.S and R.H.S]

(Z-m-z)/(x)=b [Divide by x on both sides i.e, L.H.S and R.H.S]

b= (Z-m-z)/(x)

Hope this helps you.

3 0
3 years ago
Read 2 more answers
Please need help on this having a hard time with both of these
Arlecino [84]
Question 1 - the first choice is right
Question 2- the first choice also
8 0
3 years ago
What percent of the first 20 natural numbers are prime numbers?
Brilliant_brown [7]
The primes are 2, 3, 5, 7, 11, 13, 17, 19. There are 8 of them, so they make up 40% of the numbers 1–20.
3 0
3 years ago
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Does anyone need help with simple Pythagorean theorem questions?
iren2701 [21]

Answer:

Yes

Step-by-step explanation:

Will you help me please

4 0
3 years ago
The​ life, in​ years, of a certain type of electrical switch has an exponential distribution with an average life β=44. If 100 o
Bond [772]

Answer:

0.9999

Step-by-step explanation:

Let X be the random variable that measures the time that a switch will survive.

If X has an exponential distribution with an average life β=44, then the probability that a switch will survive less than n years is given by

\bf P(X

So, the probability that a switch fails in the first year is

\bf P(X

Now we have 100 of these switches installed in different systems, and let Y be the random variable that measures the the probability that exactly k switches will fail in the first year.

Y can be modeled with a binomial distribution where the probability of “success” (failure of a switch) equals 0.0225 and  

\bf P(Y=k)=\binom{100}{k}(0.02247)^k(1-0.02247)^{100-k}

where  

\bf \binom{100}{k} equals combinations of 100 taken k at a time.

The probability that at most 15 fail during the first year is

\bf \sum_{k=0}^{15}\binom{100}{k}(0.02247)^k(1-0.02247)^{100-k}=0.9999

3 0
3 years ago
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