Once again co sines . Please help me and include explanation with a clear answer
1 answer:
Using the law os cosines formula b^2 = a^2 + c^2 - 2*a*c*cos(B)
a = 17, b = 8, c = 16
8^2 = 17^2 + 16^2 - 2*17*16* cos(B)
64 = 289 + 256 - 544 * cos(B)
544*cos(B) = 289 + 256 - 64
544 * cos(B) = 481
cos (B) = 481/544
B = arccos(481/544)
B = 27.8 degrees
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i hope it helps please mark me as brainliest please
Answer:
C is correct
Step-by-step explanation:
10x³+2x²+0x-11
+0x³+9x²+2x-2
=10x³+11x²+2x-13
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hope this helps.
Assuming CDB is a straight line then angle ADB = 180-82=98
