Answer:- | -7 + 4 |
= - | -3 | Since | -3 | = 3:
= - (3)
= - 3
Answer:
When Jamal Crawford comes to the free throw line, in the 2012-2013 NBA season, he would make 871 free throws out of 1000. Therefore, his percentage of making a free throw would by %87.1
Answer:
The value is
Step-by-step explanation:
From the question we are told that
The sample mean is 
The sample size is n = 25
The standard deviation is 
Given that the sample size is not large enough i.e n< 30 we will make use of the student t distribution table
From the question we are told the confidence level is 99.7% , hence the level of significance is
=>
Generally the degree of freedom is 
=> 
=>
Generally from the student t distribution table the critical value of
at a degree of freedom of
is
Generally the margin of error is mathematically represented as
=>
=>
Gnerally the upper control chart limit for 99.7% confidence is mathematically represented as

=>
=>
Answer:
Hello!
______________________
8.14*10=81.4 Is correct
Step-by-step explanation: Multiply 10 by 8.14.
Hope this helped you!
:D