Create at least 3 subtraction problems that have a common denominator of 20 using the fractions one sixth two fifths four sevent
1 answer:
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I wasn't sure how to order things, so I decided to write directly on top of your screenshots. Have a look at the three attachments. Two of which are correct. There is one incorrect answer though you're fairly close.
Answer:
<u>ACUTE</u><u> </u><u>TRIANGLE</u><u> </u>
Step-by-step explanation:
If the sum of the squares of the two shorter sides of a triangle is greater than the square of the longest side, the triangle is acute. However, if the sum of the squares of the two shorter sides of a triangle is smaller than the square of the longest side, the triangle is obtuse.
Therefore, the triangle with sides 11, 9, and 7 is an acute triangle since 9² + 7² is greater than 11²