A^2+b^2=c^2
A=63
B=?
C=87
63^2+b^2=87^2
3969+b^2=7569
-3969 both sides
B^2=3600
Square root both sides
B=60in
With the given order of integration, the interval over D is
Answer:
Step-by-step explanation:
If the engine torque y (in foot-pounds) of one model of car is given by y=−3.75x^2+23.2x+38.8
The engine speed is at maximum if dy/dx = 0
dy/dx = -2(3.75)x+23.2
dy/dx = -7.5x + 23.2
since dy/dx = 0
0 = -7.5x + 23.2
7.5x = 23.2
x = 23.2/7.5
x = 3.093
Hence the maximum torque is 3.09 rev/min
Answer: 1st one
Step-by-step explanation:
Answer:
11
Step-by-step explanation:
f(3)=(3)^2+2(3)-4
f(3)=9+2(3)-4
f(3)=9+6-4
f(3)=15-4
f(3)=11
