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Advocard [28]
3 years ago
7

Show me how to solve -6+x/4= -5

Mathematics
1 answer:
schepotkina [342]3 years ago
7 0
Multiply 4(-5) then add 6 and theres your X

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If two lines are perpendicular, which statement must be true? A) The product of their slopes is 1. B) Their slopes are opposites
castortr0y [4]
If two lines are perpendicular, the statement that must be true is : D. The product of their slopes is -1

Lets say that a line has a slope of 2, the line which perpendicular to that line would have a slope of -1/2

Which means, the product would be 2(-1/2) = -1

hope this helps
4 0
3 years ago
Please I need help please asap
Amanda [17]
I think the answer is D
6 0
3 years ago
CAN SOMEONE PLEASE HELP ME WITH MY GEOMETRY HOMEWORK PLEASE?
Kay [80]

Answer:

Option A

Step-by-step explanation:

The complete question is shown in the attachment.

The sum of angles in a triangle is 180 degrees.

This implies that:

m\angle A+85+53=180

m<A+138=180

m<A=180-138=42

Now we use the sine rule to find AC=b

\frac{b}{\sin 85}=\frac{85}{\sin 42}

This implies that:

b=\frac{85}{\sin 42}*\sin 85

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5 0
3 years ago
Solve the following system of equations by substation.
Cerrena [4.2K]

Answer:

C. (-1, 3)

Step-by-step explanation:

Label the 2 equations:

5y= 7x +22 -----(1)

x= -6y +17 -----(2)

Substitute (2) into (1):

5y= 7(-6y +17) +22

5y= -42y +119 +22 <em>(</em><em>Expand</em><em> </em><em>bracket</em><em>)</em>

5y= -42y +141 <em>(</em><em>Simplify</em><em>)</em>

42y +5y= 141 <em>(</em><em>+</em><em>42y</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>

47y= 141

y= 141 ÷47 <em>(</em><em>÷</em><em>4</em><em>7</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>

y= 3

Substitute y= 3 into (2):

x= -6(3) +17

x= -18 +17

x= -1

Thus, the solution is (-1, 3).

7 0
3 years ago
What digit can be in the ones place of a number that has 5 as a factor
saveliy_v [14]
Only numbers possible would be five and zero

8 0
4 years ago
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