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qaws [65]
3 years ago
8

A rectangular garden has a walk around it of width x. The garden is 20 ft by 15 ft. Write a function representing the combined w

idth A(x), of the garden
Mathematics
1 answer:
kodGreya [7K]3 years ago
5 0

Answer: A(x) = 15 ft + 2x

 

EXPLANATION

 

Given,

The dimension of the rectangular garden is 20 ft by 15 ft.

Dimension of a rectangle is written as Length by Width

This implies that,

Length of the garden = 20 ft

Width of the garden = 15 ft

 

The garden has a walk around it of width x.

The combined width of the garden = Width of garden + 2x

[we are adding twice the width of the walk because it is around the garden (this means it will add to the width of the garden on both the left and right sides)]

 

Combined width of the garden, A(x) = Width of garden + 2x

Since width of the garden = 15 ft

A(x) = 15 ft + 2x

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Answer:

10 percent is the answer

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Which of these equations are true when the value of y is 27?
Troyanec [42]

Answer:

I. -9 + y = 18

Step-by-step explanation:

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What is the value of 6P6?   A. 1   B. 36   C. 720   D. 46,656
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3 0
4 years ago
What is the area??????
Westkost [7]
Your answer would be 91.1 units².
We can split this shape into a trapezium and a semicircle, and then find the area of both and add them.
To find the area of a trapezium, the formula is
(a + b)/2 × h, which means we do 14 (the length of AD) + 8 (the length of BC) = 22, and 22/2 = 11. Then we multiply 11 by the height of the trapezium, which is 6 because 10 - 4 = 6. This gives us the area of the trapezium as 66 units².
To find the area of a semicircle, the formula is πr²/2, and the radius is 4 because the diameter is 8 (16 - 8 = 8). This means we do π4²/2 = 16π\2 = 8π = 25.13.
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7 0
3 years ago
Read 2 more answers
I will mark you as brainlis if you andwer this all.
dimaraw [331]

Answer: See below

Step-by-step explanation:

27.  -(a-3)

28.  (b-1)(b+3)

29.  (c+4)(c+5)

30.  d(d+5)

31.  -(3/4)(2e-5)

Sorry - I don't have time to enter the details.  Look for areas where the expressions can be factored in a manner that forms as many equivalent expressions in both the numerator and denominator.

For example:  In problem 30:

(5d-20)/(d^2+d-20) * [??]/20d = 1/4

Factor:  

  <u>(5(d-4))</u>       <u>d(d+5)</u>        = 1/4

(d-4)(d+5<u>)</u>       20d

The (d-4), d+5, and d terms cancel, leaving

5/20 = 1/4

7 0
3 years ago
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