Answer:
700
Explanation:
If from the question the price per unit of fertilizer, p(x) = 300 - 0.1x
The cost of x units of fertilizer = C(x) = 15000 + 125x + 0.025x^2
And we know that Profit = Revenue - Cost
Revenue for x units of fertilizer R(X) = x*p(x)
= 300x - 0.1x^2
Hence Profit: P(x) = R(x) - C(x)
= [300x - 0.1x^2] - [15000 + 125x + 0.025x^2]
= -0.125x^2 + 175x - 15000
To determine critical values
P'(x) = -0.25x + 175 = 0
Thus x = 175/0.25
x = 700
To maximize profit, the manufactures must produce 700 units of fertilizers
The answer is.. C 7
PLEASE MARK BRAINLIEST
hope this helps
Corn wheat and oats are definitely the three primary<span />
True since some of the input energy is turned into heat energy, which is then lost in the environment. This is why input work is never equal to output work, unless the problem is set in a 'perfect world'.
