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3 years ago

Solve the inequality x + 3 < 7. Which number line represents the solution? es )

Mathematics

1 answer:

Leya [2.2K]3 years ago

6 0

Answer:

x < 4

So the dot on the graph would be an open dot and the number line would be shaded to the left.

Step-by-step explanation:

I do not see a number line, but

x < 4

So the dot on the graph would be an open dot and the number line would be shaded to the left.

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I will gove brainlist ..The line graph shows the amount of water loss in a leaking tank during 7 hours.The owner pays $1for ever

kramer

Answer:

The owner will have to pay $ 125 after 2 hours.

Step-by-step explanation:

Given that the line graph shows the amount of water loss in a leaking tank during 7 hours, and the owner pays $ 1 for every 8 liters of water lost, to determine how much will he have to pay after 2 hours the following calculation must be performed :

((6000 - 5000) / 8) x 1 = X

(1000/8) x 1 = X

125 x 1 = X

125 = X

Therefore, the owner will have to pay $ 125 after 2 hours.

8 0

3 years ago

How much of the garage foot is white

Ket [755]

All you do is multiply 15 and 6 you get 90. then divide 90 by 9 and you get 10.

4 0

3 years ago

Suppose f(x)=x^2. what is the graph of g(x)=f(3x)?<br>

Katarina [22]

Answer:

Step-by-step explanation:

because since there is no negative sign in front of the 3x we automatially know there is no reflection so that rules out answers A and B. Then, since 3 is greater than 1 we can determine that it is a stretch which would rule out answer C so the answer is D

6 0

3 years ago

Find the distance from point A(−9,−3) to the line y = x−6. Round your answer to the nearest tenth.

Vladimir79 [104]

The distance from point A(−9,−3) to the line y = x−6 is 8.5 units

<u>What is slope ?</u>

A line's steepness is determined by its slope. In mathematics, slope is determined by "rise over run" (change in y divided by change in x).

step 1

Find the slope of the perpendicular line to the given line

y=x-6 ---> given line

The slope is m=1

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

m1*m2 = -1

we have

m1=1

substitute

(1)*m2 = -1

m2 = -1

step 2

Find the equation of the perpendicular line to the given line

The equation in point slope form is

y-y1=m(x-x1)

we have

m=-1

(x1,y1)=(−9,−3)

substitute

y+3=-1(x+9)--> equation in point slope form

y+3= -x-9

y= -x-12---> equation in slope intercept form

step 3

Find the intersection point between the given line and the perpendicular line to the given line

we have the system of equations

y = x−6.

y= -x-12

Solve the system by graphing

The intersection point is (-3,-9)

see the attached figure

step 4

we know that

The distance between the point A and the point (-3,-9) is the same that the distance between point A and the line y=x-6

the formula to calculate the distance between two points is equal to

d=√[(y2-y1)² + (x2-x1)²]

substitute the values

d=√[(-9+3)² + (-3+9)²]

d= √72 units

simplify

d= 6√2 = 8.5 units

To learn more about the slope from the given link

brainly.com/question/16949303

#SPJ1

8 0

10 months ago

Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III

vodka [1.7K]

Given:

$\sin x=-\dfrac{15}{17}$

x lies in the III quadrant.

To find:

The values of $\sin 2x, \cos 2x, \tan 2x$ .

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.

We know that,

$\sin^2 x+\cos^2 x=1$

$(-\dfrac{15}{17})^2+\cos^2 x=1$

$\cos^2 x=1-\dfrac{225}{289}$

$\cos x=\pm\sqrt{\dfrac{289-225}{289}}$

x lies in the III quadrant. So,

$\cos x=-\sqrt{\dfrac{64}{289}}$

$\cos x=-\dfrac{8}{17}$

Now,

$\sin 2x=2\sin x\cos x$

$\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})$

$\sin 2x=-\dfrac{240}{289}$

And,

$\cos 2x=1-2\sin^2x$

$\cos 2x=1-2(-\dfrac{15}{17})^2$

$\cos 2x=1-2(\dfrac{225}{289})$

$\cos 2x=\dfrac{289-450}{289}$

$\cos 2x=-\dfrac{161}{289}$

We know that,

$\tan 2x=\dfrac{\sin 2x}{\cos 2x}$

$\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}$

$\tan 2x=\dfrac{240}{161}$

Therefore, the required values are $\sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}$ .

7 0

2 years ago