Christy should make at least 30 bracelets and at most 40 necklaces to maximize profit
<h3>How to determine how many bead of each type of bracelets and necklaces should Christy make to maximize his profit?</h3>
The given parameters can be represented in the following tabular form:
Bracelet (x) Necklace (y) Total
Labor (hour) 0.5 0.75 40
Profit 10 18
From the above table, we have the following:
Objective function:
Max P = 10x + 18y
Subject to:
0.5x + 0.75y <= 40
Because she wants to make at least 30 bracelets, we have:
x >= 30
So, we have:
Max P = 10x + 18y
Subject to:
0.5x + 0.75y <= 40
x >= 30
Express x >= 30 as equation
x = 30
Substitute x = 30 in 0.5x + 0.75y <= 40
0.5 * 30 + 0.75y <= 40
This gives
15 + 0.75y <= 40
Subtract 15 from both sides
0.75y <= 30
Divide by 0.75
y <= 40
Hence, Christy should make at least 30 bracelets and at most 40 necklaces to maximize profit
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I believe the answer is the second answer
s < 30,000$ i dont know if this is what the question is asking but its the best i can come up with given the information you gave to me.
Answer:
x < 3 and x > -1
Step-by-step explanation:
Step 1: Subtract 2 from both sides.
Step 2: Solve absolute value.
- We know x - 1 < 2 and x - 1 > -2.
Condition 1:
Condition 2:
Therefore, the answer is x < 3 and x > -1.
5,000 is the answer to the equation
(Add 1 to both sides)
(Add 1 to both sides)