The coordinates of the point labeled A in the graph shown is (2,-2). The 2 is in the x axis while -2 is in the y axis of the graph while point B is in coordinates (-2,-2) and point C is in coordinates (-2,4).
9514 1404 393
Answer:
B. 26
Step-by-step explanation:
All acute angles in the figure are congruent. All obtuse angles in the figure are congruent. All of the even-numbered angles are acute and have the measure 26.
m∠16 = 26
Subtract 3 from both sides so that the equation becomes -2x^2 + 5x - 13 = 0.
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [ -b ± √(b^2 - 4ac) ] / (2a)
x = [ -5 ± √((5)^2 - 4(-2)(-13)) ] / ( 2(-2) )
x = [-5 ± √(25 - (104) ) ] / ( -4 )
x = [-5 ± √(-79) ] / ( -4)
Since √-79 is nonreal, the answer to this question is that there are no real solutions.
Answer:
5: c=65 d=125 e=60
6: c= 58 d= 121 e=63
7. a=55 b=64 c=61
8. a=61 b=55 c=64
Step-by-step explanation: :)
Multiply 40 and 6 and then add the remainder (16):
240+16 = 256
check by dividing "the number," 256, by 40. Is the partial quotient 6? Is there a remainder of 16? YES and YES.