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Bas_tet [7]
3 years ago
11

BRAINLIEST ASAP! PLEASE HELP ME :)

Mathematics
1 answer:
miv72 [106K]3 years ago
7 0

Answer:

○\displaystyle negatively\:skewed

Step-by-step explanation:

This is where your <em>median</em> is near the lower quartile.

I am joyous to assist you anytime.

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the stopping distance of an automobile is directly proportional to the square of its speed v. a car required 90 feet to stop whe
vesna_86 [32]
First we write the mathematical model in a generic way:
 "The stopping distance of an automobile is directly proportional to the square of its speed v"
 d = kv ^ 2
 Where,
 k: proportionality constant.
 We now look for the value of K:
 d = kv ^ 2
 90 = k ((70) * (5280/3600)) ^ 2
 k = 90 / ((70) * (5280/3600)) ^ 2
 k = 0.008538539 s ^ 2 / feet
 The equation will then be:
 d = (0.008538539) * v ^ 2
 For v = 71 miles per hour we have:
 d = (0.008538539) * ((71) * (5280/3600)) ^ 2
 d = 92.6 feet
 Answer:
 a mathematical model that gives the stopping distance in terms of its speed v is:
 d = (0.008538539) * v ^ 2
 The stopping distance if the brakes are applied when the car is traveling at 71 miles per hour is:
 d = 92.6 feet
3 0
3 years ago
A 5 foot tall student casts a shadow that is 8 feet long. A 12.5 foot flag pole close by casts a shadow with an unknown length,
prohojiy [21]

Answer:

15.5

Step-by-step explanation:

3 0
2 years ago
Which equation shows the quadratic formula used correctly to solve 7x2 = 9+ x for x?
____ [38]

Answer:

x = (1 + sqrt(253))/14 or x = (1 - sqrt(253))/14

Step-by-step explanation:

Solve for x:

7 x^2 = x + 9

Subtract x + 9 from both sides:

7 x^2 - x - 9 = 0

x = (1 ± sqrt((-1)^2 - 4×7 (-9)))/(2×7) = (1 ± sqrt(1 + 252))/14 = (1 ± sqrt(253))/14:

Answer: x = (1 + sqrt(253))/14 or x = (1 - sqrt(253))/14

6 0
3 years ago
Read 2 more answers
Are my answers correct? Precalculus!!
SVETLANKA909090 [29]

Answer:

Unfortunately, your answer is not right.

Step-by-step explanation:

The functions whose graphs do not have asymptotes are the power and the root.

The power function has no asymptote, its domain and rank are all the real.

To verify that the power function does not have an asymptote, let us make the following analysis:

The function y = x ^ n , when x approaches infinity, where does y tend? Of course it tends to infinity as well, therefore it has no horizontal asymptotes (and neither vertical nor oblique)

With respect to the function y= \frac{1}{x} we ​​can verify that if it has asymptote horizontal in y = 0. Since when x approaches infinity the function is closer to the value 0.

For example: 1/2 = 0.5;   1/1000 = 0.001;    1/100000 = 0.00001 and so on. As "x" grows "y" approaches zero

Also, when x approaches 0, the function approaches infinity, in other words, when x tends to 0 y tends to infinity. For example: 1 / 0.5 = 2; 1 / 0.1 = 10; 1 / 0.01 = 100 and so on. This means that the function also has an asymptote at x = 0

6 0
3 years ago
Please answer and no explanation needed
rewona [7]
Wait isn’t it 30 or am I reading it wrong?
3 0
2 years ago
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