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QveST [7]
3 years ago
11

The senior class at high school A rented and filled 3 vans and 6 buses with 306 students. High school B rented and filled 1 van

and 3 buses wit 144 students. Every van had the same number of students in it as did the buses. Find the number of students in each van and in each bus.
Mathematics
1 answer:
musickatia [10]3 years ago
7 0

Answer:

8 students in each van ~ 22 in each bus

Step-by-step explanation:

- Equations:

8v + 8b = 240

4v + b = 54

------

- Modify:

8v + 8b = 240

8v + 2b = 108

------

- Subtract and solve for "b":

6b = 132

b = 22 (# of students in each bus)

-----

- Solve for "v":

4v + b = 54

4v + 22 = 54

4v = 32

v = 8 (# of students in each van)

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Answer: 2.8

Step-by-step explanation:

The mean of the data set it 10. Then find the difference between the mean and each data value. |10-5|=5 do this for all of them. You get 5,1,1,1,6. Now find the mean of the these new data value. 5+1+1+1+6=14 14/5=2.8

7 0
3 years ago
Compute: 5 ∙ (2 + 3i)
dimulka [17.4K]

Answer:

It will be equal to 40

Step-by-step explanation:

We have to compute 5\times (2+3!)

Let first find 3 !

For this we have to use factorial concept

So 3! will be equal to 3! = 3×2×1 = 6

Now According to 6+2 = 8

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So 5×8 = 40

So after computation 5\times (2+3!)=40

So the final answer will be 40

4 0
4 years ago
Can you help me to solve this​
Ber [7]

Answer:

\frac{4a-2}{2a+1}

Step-by-step explanation:

Factorise the numerator and denominator

8a² - 2 ← factor out 2 from each term

= 2(4a² - 1) ← 4a² - 1 is a difference of squares

= 2(2a - 1)(2a + 1)

4a² + 4a + 1 ← is a perfect square

= (2a + 1)²

Thus

\frac{8a^2-2}{4a^2+4a+1}

= \frac{2(2a-1)(2a+1)}{(2a+1)(2a+1)} ← cancel (2a + 1) on numerator/ denominator

= \frac{2(2a-1)}{2a+1}

= \frac{4a-2}{2a+1}

3 0
3 years ago
Read 2 more answers
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Answer:

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Step-by-step explanation:

4 0
3 years ago
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6 0
3 years ago
Read 2 more answers
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