Answer:
Step-by-step explanation:
Given that the triangles are similar then the ratios of corresponding sides are equal.
To determine the scale factor calculate the ratio of corresponding sides, that is
= =
The range of the following relation R {(3, −2), (1, 2), (−1, −4), (−1, 2)} is Your answer: {−1, 1, 3} {−1, −1, 1, 3} {−4, −2, 2,
nalin [4]
Answer:
The range is all the y values.
Therefore, the range is : {-4,-2,2}.....I realize choice c has all the y values listed, however, if u have repeating y values, u only have to list it once.
Step-by-step explanation:
by solving the first equation you'll get x= -24/13
if you solve the second option (B) then you'll the same result i.e x=-24/13
so option C is correct
<span>The distributive property is: a(b + c) = ab + ac. In this expression, the example would be 8(54 + 0) = (8 x 54) + (8 x 0). The cost of eight family passes is therefore equal to 8 x 54. $432 is the answer.</span>
Answer:
There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.
Step-by-step explanation:
Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.
The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is As a result, we have 165 ways to distribute the blackboards.
If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is . Thus, there are only 35 ways to distribute the blackboards in this case.