The center of a circle whose equation is x^2 +y^2 – 12x – 2y +12 = 0 is (6,1)
<h3>Equation of a circle</h3>
The standard equation of a circle is expressed as:
x^2 + y^2 + 2gx + 2fy + c = 0
where:
(-g, -f) is the centre of the circle
Given the equations
x^2 +y^2 – 12x – 2y +12 = 0
Compare
2gx = -12x
g = -6
Simiarly
-2y = 2fy
f = -1
Centre = (6, 1)
Hence the center of a circle whose equation is x^2 +y^2 – 12x – 2y +12 = 0 is (6,1)
Learn more on equation of a circle here: brainly.com/question/1506955
Answer:
x = t
y = -t
z = (17-6t)/5
Step-by-step explanation:
First we will write down Equation 1 and Equation 2
4x-2y+5z = 17------(1)
x + y = 0--------(2)
Since we are asked to express our answer in terms of the parameter t so lets suppose x = t and y = -t
Now substitute the value of x and y in equation (1) we get
4(t) -2(-t) +5z = 17
6t + 5z = 17
5z = 17 -6t
z = (17-6t)/5
hence we get the following answer
x = t
y = -t
z= (17-6t)/5
we can also verify our answer by substituting the values of x ,y and z in any of the two equations above, for example lets substitute these values in equation 1
4(t) -2(-t) + 5((17-6t)/5)) = 17
6t + 17 -6t = 17
6t -6t = 17 -17
0 = 0
The functions in order from least to greatest according to their average rates of change are function f at the interval [1,2], function h at the interval [0,2] and function g at the interval [2,3]
<h3>How to order the functions?</h3>
The rate of change is calculated using:

For function g at the interval [2,3], we have:

This gives


For function h at the interval [0,2], we have:

Where:
h(2) = 3(3)^2 - 9 = 18
h(0) = 3(3)^0 - 9 = -6
This gives


For function f at the interval [1,2], we have:

This gives


Hence, the functions are function f at the interval [1,2], function h at the interval [0,2] and function g at the interval [2,3]
Read more about average rates of change at:
brainly.com/question/8728504
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