the common ratio in a geometric series is 4 and the first term is 3 find the sum of the first 8 terms in the series

Mathematics

2 answers:

iragen [17]3 years ago

8 0

Answer: 65535

Step-by-step explanation:

True [87]3 years ago

6 0

Answer:It’s b

Step-by-step explanation:

Girl it’s sum

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a delivry truck is transporiting boxes of two sizes large and small the combined weight of a large box and a small box is 65 pou

Semenov [28]

Answer: S = 20 lbs L = 45 lbs. Both answer have been rounded from below

Step-by-step explanation:

L+S = 65 lbs

55L + 65S = 3774 lbs

55L+55S = (65)(55) = 3,575 lbs

10S = 199 lbs

S = 19.99 (round to 20)

L + S = 65

L + 19.99 = 65

L = 45.01 (round to 45)

3 0

3 years ago

Rewrite the following equation in slope-intercept form.<br><br> –3y + 5 = –4x

snow_lady [41]

Answer:

4x+3y=5

Step-by-step explanation:

Subtract

from both sides of the equation.

3y = 5− 4x

Divide each term by 3 and simplify.

y= −4x 3+53

Rewrite in slope-intercept form.

−

4 0

3 years ago

Read 2 more answers

How to solve this :') please help

blsea [12.9K]

Answer:

3/2

Step-by-step explanation:

sin(3π/4 - β) = sin(3π/4)cosβ - cos(3π/4)sinπ =

$\sin(\frac{3\pi}{4}-\beta)=\sin(\frac{3\pi}{4})\cos\beta-\cos\frac{3\pi}{4}\sin\beta\\=\frac{1}{\sqrt{2}}\cos\beta-(-\frac{1}{\sqrt{2}})\sin\beta\\\\=\frac{1}{\sqrt{2}}(\cos\beta +\sin\beta)\\\\\sin^2(\frac{3\pi}{4}-\beta)=\frac{1}{2}\cos\beta +\sin\beta)^2=\frac{1}{2}(\cos^2\beta +\sin^2\beta+2\sin\beta\cos\beta\\=\frac{1}{2}(1+\sin2\beta)=\frac{1}{2}(1-\frac{1}{5}) = \frac{2}{5}\\$