Question

what are thd center and radius of the circle with equation (x+4)to the second power + (y-3) to the power 2 =36

Answer 1

(x+4)² + (y-3)² = 36

General equation for the circle is
(x-h)² +(y-k)² = 36,  where (h, k) is a center.

So for our equation  h=-4, k =3. The center is (-4, 3).

Check
(x-(-4))² +(y -3)²=36 ----->    (x+4)² + (y-3)² = 36
 

Answer 2

(h,k) the cinter of the circle
(-4,3)
R=6 the redius of the circle