Answer:
Option A is the correct answer.
Explanation:
The instantaneous acceleration = Change in velocity in velocity/Time taken
The slope of the graph should give instantaneous acceleration.
Slope of a graph = Change in value of Y -axis / Change in values of X -axis
Comparing both the equations
Change in value of Y -axis = Change in velocity in velocity
Change in values of X -axis = Time taken
So velocity values should be on the Y axis and Time values should be on the X axis.
Option A is the correct answer.
Answer:
(a) 83.73 rad/s
(b) 251.2 m/s
(c) 3505.4 rad/s^2
(d) 5024 m
Explanation:
R = 50 cm = 0.5 m, f = 800 rpm = 800 / 60 rps
(a) Angular velocity, w = 2 x 3.14 x f = 2 x 3.14 x 800 / 60 = 83.73 rad / s
(b) The relation between linear speed and the angular speed is
V = r w
Here, r = 30 cm = 0.3 m
V = 0.3 x 83.73 = 25.12 m/s
(c) Radial acceleration = R w^2 = 0.5 x 83.73 x 83.73 = 3505.4 rad/s^2
(d) Time period T = 2 x 3.14 / w
T = 2 x 3.14 / 83.73 = 0.075 sec
In 0.075 second, angle turn = 360 degree
In 120 second, the angle turn = 360 x 120 / 0.075 = 576000 degree
In 360 degree, the distance traveled = 2 x pi x R
In 576000 degree, the distance traveled = 2 x 3.14 x 0.5 x 576000 / 360
= 5024 m
Answer:
Delta pressure = 45938[Pa]
Explanation:
This is a classic bernoulli equation problem, but first we must find the velocity at both ends of the pipe, knowing the diameters of each end.
Now we can calculate the two velocites VA and VB
Using the bernoulli equation we have:
Where ro = density of water = 1000[kg/m^3]
C is the answer to the first one