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Inessa05 [86]
3 years ago
10

Label the producers and consumers, then label the different types of consumers.

Physics
1 answer:
sdas [7]3 years ago
3 0
The base of the pyramid has the producers and everything else above the base falls under the consumers category i.e the locusts,frogs and the snake. The grass is the producer, the locust is a consumer, the frog is a special type of omnivore, termed the "life-history omnivore" since they eat both plants and animals but at different times in their lives. In this case they are just omnivores and lastly, the snake is a carnivore.
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A 2.0 µF capacitor is charged through a 50,000 ohm resistor. How long does it take for the capacitor to reach 90% of full charge
Nesterboy [21]

Answer:

0.23 s

Explanation:

First of all, let's find the time constant of the circuit:

\tau=RC

where

R=50,000 \Omega is the resistance

C=2.0\mu F=2.0\cdot 10^{-6}F is the capacitance

Substituting,

\tau=(50,000 \Omega)(2.0\cdot 10^{-6}F)=0.1 s

The charge on a charging capacitor is given by

Q(t)=Q_0 (1-e^{-t/\tau} ) (1)

where

Q_0 is the full charge

we want to find the time t at which the capacitor reaches 90% of the full charge, so the time t at which

Q(t)=0.90 Q_0

Substituting this into eq.(1) we find

0.90 Q_0 = Q_0 (1-e^{-t/\tau})\\0.90=1-e^{-t/\tau}\\e^{-t/\tau}=1-0.90=0.10\\-\frac{t}{\tau}=ln(0.10)\\t=-\tau ln(0.10)=(0.1 s)ln(0.10)=0.23 s

4 0
3 years ago
A uniform 1500-kg beam, 20.0 m long, supports a 15,000-kg printing press
Ghella [55]

Answer:

\mathbf{F_1=4.41*10^4\ N}

\mathbf{F_2 = 1.176*10^5 \ N}

Explanation:

The missing image of the figure slide is attached in below.

However, from the model, it is obvious that it is in equilibrium.

As a result, the relation of the force and the torque is said to be zero.

i.e.

\sum F = 0 and \sum \tau = 0

From the image, expressing the forces through the y-axis, we have:

F_1+F_2 = W_B + W_P \\ \\ \implies 9.8(1500+15000) \\ \\ \implies  \mathtt{1.617\times 10^5 \ N}

Also, let the force F_1 be the pivot and computing the torque to determine F_2:

Then:

F_1(0)+F_2(20.0) = 10.0W_B + 15.0W_P

F_2 = \dfrac{((10*1500)+(15*15000))*9.8}{20.0}

F_2 = 117600 \ N

\mathbf{F_2 = 1.176*10^5 \ N}

For the force equation:

F_1+F_2=1.617*10^5 \ N;

where:

F_2 = 1.176*10^5 \ N

Then:

F_1+1.176*10^5 \ N=1.617*10^5 \ N

F_1=1.617*10^5 \ N-1.176*10^5 \ N

F_1=44100\ N

\mathbf{F_1=4.41*10^4\ N}

8 0
3 years ago
A golf ball is dropped from rest from a height of 9.50m. It hits the pavement, then bounces back up, rising just 5.70m before fa
marta [7]

Answer:

Explanation:

Given

height from which ball is dropped h_1=9.5\ m

and it rises to a height of h_2=5.7\ m

A person caught the ball in mid-way i.e. at a height of h_0=1.2\ m from pavement

time taken to reach the bottom is given by

y=ut+\frac{1}{2}at^2

where  y=displacement

u=initial velocity

a=acceleration

t=time

here initial velocity is zero i.e.

h_1=0+\frac{1}{2}gt_1^2

t_1=\sqrt{\frac{2h_1}{g}}

Similarly to reach of  height h_2 time taken is t_2

t_2=\sqrt{\frac{2h_2}{g}}

The ball is caught in mid-way i.e. ball travel a distance of h_3=5.7-1.2=4.5\ m

time taken is t_3=\sqrt{\frac{2h_3}{g}}

total time taken t=t_1+t_2+t_3

t=\sqrt{\frac{2h_1}{g}}+\sqrt{\frac{2h_2}{g}}+\sqrt{\frac{2h_3}{g}}

t=\sqrt{\frac{2\cdot 9.5}{9.8}}+\sqrt{\frac{2\cdot 5.7}{9.8}}+\sqrt{\frac{2\cdot 4.5}{9.8}}

t=3.429\ s

total time =3.429 s

4 0
3 years ago
Any clue on this one please help
IceJOKER [234]
The third one is your answer
7 0
3 years ago
How does the moons diameter compare with the distance between the earth and the moon?
xxMikexx [17]
The diameter is about 0.9 percent of the distance.
7 0
3 years ago
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