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mrs_skeptik [129]
3 years ago
8

Which choice is equivalent to the fraction below? (Hint: Rationalize the denominator and simplify.) I NEED HELP HELP PLEASE PLEA

SE HELP HELP PLEASE HELP ME PLEASE PLEASE HELP PLEASE PLEASE ASAP PLEASE PLEASE THANK

Mathematics
2 answers:
nadya68 [22]3 years ago
4 0

Answer:

Option A.

Step-by-step explanation:

The given fraction \frac{2}{\sqrt{x}\sqrt{x+2}} is to be simplified.

For the simplification of the given fraction we will rationalize the denominator. By multiplying (\sqrt{x}\sqrt{x+2}) in numerator as well as denominator both, denominator can be rationalized.

\frac{2(\sqrt{x}-\sqrt{x+2})}{(\sqrt{x}+\sqrt{x+2})(\sqrt{x}-\sqrt{x+2})}

= \frac{2(\sqrt{x}-\sqrt{x+2})}{(\sqrt{x})^{2}-(\sqrt{x+2})^{2} }

[ Since ( a+b) (a-b) = a² - b² ]

\frac{2(\sqrt{x}-\sqrt{x+2)}}{x-(x+2)}=\frac{(2\sqrt{x}-\sqrt{x+2)}}{(-2)}

= -(\sqrt{x}-\sqrt{x+2}=\sqrt{x+2}-\sqrt{x}

Option A. is the answer.

sladkih [1.3K]3 years ago
3 0

Answer:

A: \sqrt{x + 2} - \sqrt{x}

^.^

- Amanda

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